Answer:
0 < y <= 6
Step-by-step explanation:
Given:
√(x² - 6x + 9)
if -3 <= x < 3
you can write (x² - 6x + 9)
as (x-3) * (x- 3) which is (x-3)²
so now you have √{(x-3)²}, which is the same as the absolute value of x-3. In mathematics it is written as:
| x - 3 |
So √(x² - 6x + 9) = | x - 3 |
See the graph in the attachment.
for -3 <= x < 3
you get the y values bigger then ( but not equal to) 0 and smaller then or equal to 6.
This is written as 0 < y <= 6
15)
∠EAD ≅ ∠CAB . . . . . . reflexive property. An angle is congruent with itself.
∠AED ≅ ∠ACB . . . . . . given
ΔABC ≅ ΔADE . . . . . . angle-angle similarity: If two angles are congruent, all three angles are congruent and the triangles are similar.
The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
<h3>What is the approximation about?</h3>
From the question:
Mars: F(x) = 2/3
Therefore, If x = 15
Then:
f (15) = 2/3
= 16/3
= 20.7ft/s
Hence, The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
Learn more about Estimation from
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Answer:
reciprocal
Step-by-step explanation:
mark me brainliest pls
Step-by-step explanation:
Let's start with solving for line L using slope-intercept form (y=mx+b)
We can see that the y-intercept is 4, and the slope is rise/run. From point (5,2) to (0,5), the rise is 2, and the run is -5 (it goes backwards 5).
Using this, we can form our equation for Line L: y = -2/5x + 4
Now let's solve for Line M.
There is something very important to notice before we jump into this. Both of these lines (Line L and M) are parallel (they never touch) and therefore will contain the same slope as each other (-2/5). The y-intercept for this equation we can see is -1, as the line touches (0,-1). Now lets form our equation;
Line M: y = -2/5+4
Solving a system of equation means to find two (or more) line's interceptions on a graph (where they meet/touch). Because both of these lines are parallel and never touch each other, there is no definite answer. Therefore our answer is No Solutions.