We need to know that the diagonal AC is congruent to itself and we also need to know that AD and BC are congruent
Hope this helps :)
Answer:
(x, y) = (6, -2)
Step-by-step explanation:
Sometimes this solution method is called "addition" or "elimination." You want to multiply one or both equations by a value or values that make the coefficients of one of the variables be opposites. Then when you add the equations, the result is an equation without that variable. (One variable has been eliminated.)
Multiply the first equation by -2 to make its x-coefficient the opposite of that in the second equation. Then add the two equations:
-2(3x +3y) = -2(12)
-6x -6y = -24
Add the second equation ...
(-6x -6y) +(6x +11y) = (-24) +(14)
5y = -10 . . . . . simplify
y = -2 . . . . . . . divide by 5
__
3x +3(-2) = 12 . . . . . substitute into the first equation
3x = 18 . . . . . . . . . . add 6
x = 6 . . . . . . . . . . . . divide by 3
The solution is (x, y) = (6, -2).
Answer: Last option
Step-by-step explanation:
I've attached the answer
Answer 14.03
Tan 41/1= 12.2/x
Answer:
Equation of the line; y=x+3
Step-by-step explanation:
Graph the line that passes through the points (5,8) and (3,6) and determine the equation of the line.
Equation of a line: y=mx +b
Let's find the slope:
8-6/ 5-3= 2/2 = 1
y=x+b
Substitute the points in.
y= 8
x = 5
8 = 5+b
b= 3
The y-intercept is 3.
y=x+3
Points on the line: (-2,1) (-1,2) (0,3) (1,4) (2,5)