Pythagorean thoerem
we imagine the wall as a leg of a right triangle, the ladder is the hypotonuse and the distance from the bottom of the ladder to the wall is the other leg
so if we have a right triangle with leg length a and b and hypotnuse length c then
a²+b²=c²
so
given that one of the legs is 9ft (9 ft is the height of the triangle)
and the hypotnuse is 12 ft (length of ladder)
then say the last leg is x
so
x²+9²=12²
x²+81=144
mius 81 both sides
x²=63
sqrt both sides
x=√63
x=3√7
you should place it 3√7ft or about 7.9 or 8ft away
Answer:
Step-by-step explanation:
hello :
cot x + 2cot x sin x = 0 0≤ x≤ 180
cotx(1+2sinx) =0 means : cotx=0 or 1+2sinx=0
1) cotx=0 so : cosx=0 and sinx ≠ 0 because cotx = cosx/sinx
when : 0≤ x≤ 180 : x=90°
2) 1+2sinx=0 means : sinx = -1/2
when : 0≤ x≤ 180 : no solutions because : sinx ≥ 0
conclusion : one solution : x=90°
Answer:

Step-by-step explanation:
Let
d ------> the number of days
c -----> the cost
we know that
The cost is equal to the number of days multiplied by $2 per day plus the initial fee of $5
The linear equation in slope-intercept form is

where
m is the slope
b is the c-intercept (value of c when the value of d is equal to zero)
in this problem we have
m=$2 per day
b=$5
substitute

Answer:
A) the value of the car will be 13,333.34 after 3 years ( not sure )
B) the depreciation of the car will be 2222.22 per year ( not sure)
C) i do not know