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zvonat [6]
3 years ago
12

A local drive in theatre sells entrance tickets for cars on weekend nights. At compacity, the drive in can hold 72 cars. The fun

ction C(n)=25n represents the drive in' s revenue on a weekend night, where n represents the number of cars. In this situation, what is the domain of C(n)
Mathematics
2 answers:
Deffense [45]3 years ago
8 0

Answer with explanation:

On the Weekend night, Number of cars that Drive in Can Hold =72

Minimum number of cars that can be on any weekend night = 0

Maximum number of cars that can be on any weekend night = 72

It is also given that, C(n)= 25 n, represents the drive in's revenue on a weekend night.

As, the, 0≤ number of cars(n) ≤ 72 , where n=1,2,3,4,5,6.......72.

So→, 25 × 0 ≤ C (n) ≤ 25 × 72

→ 0 ≤ C(n) ≤ 1800

So, if number of cars,

0≤ (n) ≤ 72, then

0 ≤ C(n) ≤ 1800

Domain of C(n) =[0,1800],for, n∈[0,72]

Paraphin [41]3 years ago
4 0
All positive integers less than or equal to 72<span />
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3 years ago
Need Help Answer Please!!
stepan [7]

Answer:

The correct option is B

Step-by-step explanation:

The equation of a line in point-slope form is:

y-y1 = m(x-x1)

where m is the slope and (x1,y1) a point on the line

here m=2 and (x1,y1)=(2,3)

substitute these values into the equation.

y-3 =2(x-2)

Thus the correct opttion is B....

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3 years ago
A bag contains 9 red marbles and 18 blue marbles. If a representative sample contains 2 red ​marbles, then how many blue marbles
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4 0
3 years ago
Nadia finds out that her favorite horse family population is increasing at a constant rate. The horse family was at 24 in 2011 a
Dahasolnce [82]
\begin{gathered} y-24=\frac{8}{3}(x-2011) \\ \text{There will be 48 horses in 2020 (option A)} \end{gathered}Explanation:

The initial number of horses = 24

year = 2011

Coordinates (2011, 24)

when the number of horses became 32, year was 2014

Coordinates (2014, 32)

We find the slope = rate of change

slope = change in number of horses/change in number of years

slope = (32-24)/(2014-2011)

slope = 8/3

The point slope formula:

\begin{gathered} y-y_1=m(x-x_1) \\ U\sin gpoint\colon x_1=2011,y_1=24 \end{gathered}y-24=\frac{8}{3}(x-2011)

The number of horses in year 2020

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8/3 = (y - 24)/(2020 - 2011)

8/3 = (y - 24)/9

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Hence, there will be 48horses in 2020 (option A)

4 0
1 year ago
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