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zvonat [6]
2 years ago
12

A local drive in theatre sells entrance tickets for cars on weekend nights. At compacity, the drive in can hold 72 cars. The fun

ction C(n)=25n represents the drive in' s revenue on a weekend night, where n represents the number of cars. In this situation, what is the domain of C(n)
Mathematics
2 answers:
Deffense [45]2 years ago
8 0

Answer with explanation:

On the Weekend night, Number of cars that Drive in Can Hold =72

Minimum number of cars that can be on any weekend night = 0

Maximum number of cars that can be on any weekend night = 72

It is also given that, C(n)= 25 n, represents the drive in's revenue on a weekend night.

As, the, 0≤ number of cars(n) ≤ 72 , where n=1,2,3,4,5,6.......72.

So→, 25 × 0 ≤ C (n) ≤ 25 × 72

→ 0 ≤ C(n) ≤ 1800

So, if number of cars,

0≤ (n) ≤ 72, then

0 ≤ C(n) ≤ 1800

Domain of C(n) =[0,1800],for, n∈[0,72]

Paraphin [41]2 years ago
4 0
All positive integers less than or equal to 72<span />
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One positive integer is 1 greater than 3 times another positive integer. If the product of the two integers is 154, then what is
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Answer:

29

Step-by-step explanation:

Let the smaller integer be x.

The other integer is 1 greater than 3 times x, or 3x + 1.

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x(3x + 1) = 154

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157 = 2 * 7 * 11

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(3x + 22)(x - 7) = 0

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-22/3 is not a positive integer, so we discard that solution.

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Answer:

I. A' =  (5,-5), B' = (-1,6), C' = (6,1)

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III. A' = (-5,-2), B = (6,4), C' = (1,-3)

Step-by-step explanation:

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This rule changes (x,y) to (x+3,y).

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So, the new vertices are given by,

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B = (-4,6) implies B = (6,4)

C = (3,1) implies C' = (1,-3)

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