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3 years ago

The sides of a triangle are in the ratio 3:4:5. What is the length of each side if the perimeter of

Mathematics

1 answer:

lara31 [8.8K]3 years ago

7 0

Answer:

first side =9,second side =12,third side =15

Step-by-step explanation:

total ratio =3+4+5

=12

first side=3/12×36

second side=4/12×36

=12

=third side=5/12×36

=15

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A city has a population of 230,000 people. Suppose that each year the population grows by 8.5%. What will the population be afte

worty [1.4K]

Answer:

720,682.92

Step-by-step explanation:

8.5% = 0.085

P(t) = Initial Population * (1 + rate)t

P(t) = 230,000(1 + 0.085)t

P(t) = 230,000(1.085)t

P(14) = 230,000(1.085)14

P(14) = 720,682.82

6 0

3 years ago

Identify the graph of f(x)=4^x

Wittaler [7]

Answer:

the first one

Step-by-step explanation:

The correct one is the one in the top left corner.

A great website to find out things like this is

https://www.mathpapa.com/algebra-calculator.html

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3 years ago

The difference of two number is 3. Their sum is 13. Find the numbers.

Sloan [31]

Answer:

8 and 5

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Is 8.27 rational or irrational?

BlackZzzverrR [31]

Answer:

Rational

Step-by-step explanation:

A terminating decimal is a rational number.

A repeating decimal is a irrational number.

Since 8.27 terminates, it is rational.

3 0

3 years ago

Read 2 more answers

A simple random sample of items resulted in a sample mean of . The population standard deviation is . a. Compute the confidence

Varvara68 [4.7K]

Answer:

(a): The 95% confidence interval is (46.4, 53.6)

(b): The 95% confidence interval is (47.9, 52.1)

(c): Larger sample gives a smaller margin of error.

Step-by-step explanation:

Given

$n = 30$ -- sample size

$\bar x = 50$ -- sample mean

$\sigma = 10$ --- sample standard deviation

Solving (a): The confidence interval of the population mean

Calculate the standard error

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{10}{\sqrt {30}}$

$\sigma_x = \frac{10}{5.478}$

$\sigma_x = 1.825$

The 95% confidence interval for the z value is:

$z = 1.960$

Calculate margin of error (E)

$E = z * \sigma_x$

$E = 1.960 * 1.825$

$E = 3.577$

The confidence bound is:

$Lower = \bar x - E$

$Lower = 50 - 3.577$

$Lower = 46.423$

$Lower = 46.4$ --- approximated

$Upper = \bar x + E$

$Upper = 50 + 3.577$

$Upper = 53.577$

$Upper = 53.6$ --- approximated

So, the 95% confidence interval is (46.4, 53.6)

Solving (b): The confidence interval of the population mean if mean = 90

First, calculate the standard error of the mean

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{10}{\sqrt {90}}$

$\sigma_x = \frac{10}{9.49}$

$\sigma_x = 1.054$

The 95% confidence interval for the z value is:

$z = 1.960$

Calculate margin of error (E)

$E = z * \sigma_x$

$E = 1.960 * 1.054$

$E = 2.06584$

The confidence bound is:

$Lower = \bar x - E$

$Lower = 50 - 2.06584$

$Lower = 47.93416$

$Lower = 47.9$ --- approximated

$Upper = \bar x + E$

$Upper = 50 + 2.06584$

$Upper = 52.06584$

$Upper = 52.1$ --- approximated

So, the 95% confidence interval is (47.9, 52.1)

Solving (c): Effect of larger sample size on margin of error

In (a), we have:

$n = 30$ $E = 3.577$

In (b), we have:

$n = 90$ $E = 2.06584$

Notice that the margin of error decreases when the sample size increases.

4 0

3 years ago