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Marat540 [252]
2 years ago
10

If tan 0= -(3)/(8), which expression is equivalent to cot 0 ?

Mathematics
2 answers:
IgorLugansk [536]2 years ago
8 0
Tan x = sin x / cos x

cot x = cos x/ sin x

We can see that tan and cot are reciprocal.

So, if tan(O)  = -(3)/(8), then cot(O) = - (8)/3.
DochEvi [55]2 years ago
8 0
<h2>Answer:</h2>

Hence, the answer is:

      \cot O=\dfrac{1}{\dfrac{-3}{8}} or  \cot 0=\dfrac{-8}{3}

<h2>Step-by-step explanation:</h2>

We know that the tangent trignometric function and the cotangent trignometric function is given by:

         \tan x=\dfrac{1}{\cot x}

i.e. the tangent function and the cotangent function are inverse of each other.

We are given tangent of an angle O as:

\tan 0=\dfrac{-3}{8}

Hence, we have:

\cot O=\dfrac{1}{\tan O}\\\\i.e.\\\\\cot O=\dfrac{1}{\dfrac{-3}{8}}\\\\i.e.\\\\\cot O=\dfrac{8}{-3}\\\\i.e.\\\\\cot 0=\dfrac{-8}{3}

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4 0
3 years ago
Hi, Could anyone help me with my homework
tatiyna

Answer:

\hookrightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

solving steps:

\rightarrow \sf (x + 4)^6

\bold{rewrite \ the \ following}

\rightarrow \sf (x + 4)^2   (x + 4)^2   (x + 4)^2

\bold {formula \ used : \sf  (x+a)^2 = (x^2 + 2xa + a^2)}

\rightarrow \sf (x^2 + 8x+16)    (x^2 + 8x+16)    (x^2 + 8x+16)

\bold{simplify \ by  \ removing \ parenthesis}

\rightarrow \sf (x^4 +8x^3 + 16x^2 + 8x^3 +64x^2 + 128x+16x^2+128x+256 ) (x^2 + 8x+16)

\bold{basic \ addition \ of \ integers }

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