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lara [203]
3 years ago
14

The length of a rectangular garden is 7 meters longer than its width. if its perimeter is ( 12 x + 14) meters, find its length i

n terms of x.
Mathematics
1 answer:
cluponka [151]3 years ago
7 0
L=7+w
P=(12x+14)=2(6x+7)
l+w= P/2 = 2(6x+7)/2= 6x+7
l+w=6x+7
2l = 6x+7
l = (6x+7)/2
l=7+w
-> w= l-7
= [(6x+7)/2] -7
= (6x+7-14)/2
= (6x-7)/2

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Please help me AAAAAA
bezimeni [28]

Answer:

45

Step-by-step explanation:

AEF is a similar triangle to ABC. that means it has the same angles, and the sides (and all other lines in the triangle) are scaled from the ABC length to the AEF length by the same factor f.

now, what is f ?

we know this from the relation of AC to FA.

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so, going from AC to FA we multiply AC by f so that

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all other sides, heights, ... if ABC translate to their smaller counterparts in AEF by that multiplication with f (= 3/10).

the area of a triangle is

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baseline small = baseline large × f

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we know that

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aAEF = baseline small × height small / 2 =

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8 0
3 years ago
How would you solve cos(5x)=sin(10x) ?
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cos (5x ) = 2 cos (5x ) sin ( 5x )
cos ( 5 x) - 2 cos ( 5 x ) sin ( 5x ) = 0
cos ( 5 x ) · [ 1 - 2 sin (5 x) ] = 0
cos ( 5 x ) = 0                    or :       1 - 2 sin (5 x) = 0
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x1 = π/10 + kπ/5                           5 x = π/6+2kπ    , k∈ Z
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4 0
3 years ago
Solve this .....................​
ycow [4]

Answer:

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28x=10

x = 10/28

x = 0.35

Hope it helped u,

pls mark as the brainliest

^v^

5 0
3 years ago
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