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weqwewe [10]
3 years ago
8

A 30-foot guide wire is attached to the top of the tree and then staked into the ground 25 feet away from the base of the tree.

Mathematics
1 answer:
ladessa [460]3 years ago
5 0

Answer:

16.6 feets .

Step-by-step explanation:

Length of wire = 30 feets

Distance between base of tree and ground = 25 feets

Height of tree, h

Using Pythagoras rule :

h² = 30² - 25²

h² = 900 - 625

h² = 275

h = sqrt(275)

h = 16.583

h = 16.6 feets

Height of tree is 16.6 feets

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Part A<br> How can you determine whether JKL = PQR?<br><br> Part B<br> Is JKL = PQR
kotegsom [21]

Answer:

JKL = PQR and JKL = PQR

Step-by-step explanation:

7 0
3 years ago
three friends earned more then $200 washing cars. they paid their parents $28 for supplies and divides the rest of money equally
Allushta [10]
X is each friend
3x + 28 > 200
3x > 172
x > $57.33
5 0
3 years ago
If one factor of x2 2x â€" 24 is (x 6), what is the other factor? (x 8) (xâ€"8) (x 4) (xâ’4).
FrozenT [24]

The correct question is; x² + 2x - 24

The other factor of <em>x² </em><em>+</em><em> </em><em>2x </em><em>-</em><em> 24</em> asides (x+6) is; (x-4)

The expression given can be factorised as follows;

  • x² + 6x -4x - 24

  • x(x+6) -4(x+6)

  • (x+6) (x-4).

Consequently, the other factor of the expression is (x-4).

Read more on quadratic factors;

brainly.com/question/14718354

4 0
2 years ago
Square ABCD has a diagonal of 8 inches long. How many square inches is the area of the shape?
Sunny_sXe [5.5K]
Area A of a square with side length a:  A = a².

Pythagoras theorem: a² + b² = c² 

2*a² = 8²

A = 8²/2

4 0
3 years ago
Assume that the number of customers who arrive at a water ice stand follows the Poisson distribution with an average rate of 6.4
Nady [450]

Answer:

18.88% probability that three or four customers will arrive during the next 30 minutes

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

Average rate of 6.4 per 30 minutes.

This means that \mu = 6.4

What is the probability that three or four customers will arrive during the next 30 minutes?

P = P(X = 3) + P(X = 4)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 3) = \frac{e^{-6.4}*(6.4)^{3}}{(3)!} = 0.0726

P(X = 4) = \frac{e^{-6.4}*(6.4)^{4}}{(4)!} = 0.1162

P = P(X = 3) + P(X = 4) = 0.0726 + 0.1162 = 0.1888

18.88% probability that three or four customers will arrive during the next 30 minutes

4 0
3 years ago
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