Question

A line intersects the points (-4,6) and (-2,5). what is the slope intercept equation for this line

Answer 1

First find the slope of the line connecting these two points:

6-5

m = ------------ = -1/2

-4+2

Substitute this slope into y = mx + b: y = (-1/2)x + b.

Next, subst. 5 for y and -2 for x, and find b:

5 = (-1/2)(-2) + b, or 5-1=b. Then b = 4, and

the equation of the line is y = (-1/2)x + 4.

Answer 2

First you find the slope of the equation using the formula
M= y2-y1/x2-x1
M= 5-6/-2-(-4)
M= -1/2
Using slope intercept form which is y=mx+b, you write y=-1/2x+b
Now in order to find b you simple substitute one of the given points
I choose (-4,6)
6=-1/2(-4)+b
6=2+b
b=4
So final answer would be y=-1/2x+4