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4 years ago

Identify the Domain of Composite Functions

Mathematics

2 answers:

AlexFokin [52]4 years ago

6 0

Answer:

D. There are no restrictions

Step-by-step explanation:

f(g(x)) = (x-2) + 5

= x - 2 + 5

= x+3

And since x + 3 is just a line, there are no domain restrictions.

Drupady [299]4 years ago

4 0

Answer:

The answer is B on edge

Step-by-step explanation:

i got it right

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Use the grouping method to factor the polynomial below completely.<br> +3 - 4x² + 3x - 12

ahrayia [7]

Answer:

The answer is “B”

Step-by-step explanation:

Group and factor out the greatest common factor (GCF), then combine.

3 0

3 years ago

Add the following values.<br> (2.1 × 1016) + (3.2 × 1015)

qwelly [4]

Answer:

5381.6

Step-by-step explanation:

$(2.1 × 1016) + (3.2 × 1015)$

$= 5381.6$

8 0

3 years ago

Convert the units of measure as indicated<br><br> 11 ft/s to mi/h

Tanzania [10]

Answer:

7.5miles per hour

6 0

3 years ago

Read 2 more answers

I need help with these questions

ASHA 777 [7]

Answer:

1. n = 13

2. x = -30

3. y > -18

4. n < -0.75

5. 101 t-shirts

Step-by-step explanation:

1. multiply both sides by 2, then add both sides by 2, making n = 13

2. divide both sides by -3, then subtract both sides by 5 making x = -30

3. divide both sides by -2, when dividing by a negative number, you need to switch the inequality sign to the other side

4. divide both sides by 4, then divide by -2(you need to switch the inequality sign to the other side), then add -8 and 2.5, then add 5.5 to both sides

5. the equation is 150 = 5x - 45. 45 is because they have already earned it, and 5x is how much each shirt will cost. The solution is then 101.

Hope this has a helped a little at least :P

8 0

3 years ago

Find a solution to y'(t) = te^-t satisfying the condition y(1) = 1.

Alex_Xolod [135]

Answer:

$y=-e^{-t}(t+1)+1+\frac{2}{e}$

Step-by-step explanation:

The given differential equation is

$y'(t)=te^{-t}$

It can be written as

$\frac{dy}{dt}=te^{-t}$

$dy=te^{-t}dt$

Integrate both sides.

$\int dy=\int te^{-t}dt$

Apply ILATE rule on right side. Here, t is first function and $e^{-t}$ is the second function.

$y=t\int e^{-t}-\int (\frac{d}{dt}t\int e^{-t})$

$y=-te^{-t}-\int (1\times (-e^{-t}))$ $\int e^{-x}=-e^{-x}+C$

$y=-te^{-t}+\int e^{-t}$

$y=-te^{-t}-e^{-t}+C$ .... (1)

Initial condition is y(1) = 1. It means at t=1 the value of y is 1.

$1=-(1)e^{-t}-e^{-(1)}+C$

$1=-e^{-1}-e^{-1}+C$

$1=-2e^{-1}+C$

$1=-\frac{2}{e}+C$

Add $\frac{2}{e}$ on both sides.

$1+\frac{2}{e}=C$

Substitute the value of C in equation (1).

$y=-te^{-t}-e^{-t}+1+\frac{2}{e}$

$y=-e^{-t}(t+1)+1+\frac{2}{e}$

Therefore, the solution of given initial value problem is $y=-e^{-t}(t+1)+1+\frac{2}{e}$ .

4 0

3 years ago