The angle m∠AFE is 128 degrees.
<h3>How to find angles?</h3>
∠AFB ≅ ∠EFD
∠EFD = 5x + 6
m∠DFC = (19x - 15)°
m∠EFC = (17x + 19)°
m∠AFE = ?
m∠AFB + m ∠EFD + m∠AFE = 180
Therefore,
5x + 6 + 5x + 6 + m∠AFE = 180
5x + 5x + 6 + 6 + m∠AFE = 180
10x + 12 + m∠AFE = 180
10x + m∠AFE = 180 - 12
10x + m∠AFE = 168
m∠AFE = 168 - 10x
m∠EFC = m ∠EFD + m∠DFC
17x + 19 = 5x + 6 + 19x - 15
17x - 5x - 19x = 6 - 15 - 19
-7x = - 28
x = 28 / 7
x = 4
Therefore,
m∠AFE = 168 - 10x
m∠AFE = 168 - 10(4)
m∠AFE = 168 - 40
m∠AFE = 128°
Therefore, the angle m∠AFE = 128°
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Step-by-step explanation:
l x 3 = c
k + 5 = l
(c + l + k) x 2 = 25
c = 33
l = 11
k = 6
Answer:
The hypotenuse is square root of 65
Step-by-step explanation:
a^2 + b^2 = c^2
legs of the right triangle are a and b. Just substitute 4 for a and 7 for b and solve.
4^2+7^2=16+49=65
c^2=65
Find the square root of both sides to get
c=the square root of 65
Answer:
102 feet.
Step-by-step explanation:
-23ft + 125ft = 102 ft
