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Solnce55 [7]
3 years ago
9

Answer fast

Mathematics
1 answer:
hoa [83]3 years ago
4 0

Answer:

a graph of curve is linear

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Find the midpoint between A and B, given that A=(-1,5) and B=(-3,-7)
Kamila [148]
Hello here is a solution :
<span> midpoint between A and B,is :C( (Xa+xb)/2; (ya+yb)/2)
C( (-1-3)/2;(5-7)/2)
C(-2 ; -1)</span>
6 0
3 years ago
I need help! ill give brainliest!
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area =  DC \times EG

area = 27 \times 16

area = 432

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5 0
3 years ago
I don't know how to do this
vesna_86 [32]
He could have 30 dimes and 13 quartars
7 0
3 years ago
Can someone please help me ;-; this is due today
IRISSAK [1]

Answer:

The correct answer: F (Scalene) and A (Acute)

Step-by-step explanation:

F. (Scalene):  By definition, a scalene triangle is a triangle that has no equal sides, and no equal angles. This definition matches your given triangle, since it has no equal sides and angles.

A. (Acute): By definition, an acute triangle is a triangle in which all the internal angles are less than 90 degrees. This definition matches your given triangle, since all of the internal angles are less than 90 degrees.

The given triangle is not obtuse, equilateral, right, and isoceles.

It is <u>not</u> an <em>obtuse </em>triangle because none of the angles are greater than 90 degrees.

It is <u>not</u> an <em>equilateral</em> triangle because its sides are not equal.

It is <u>not</u> a <em>right</em> triangle because none of its internal angles measure 90 degrees.

And it is <u>not</u> an <em>isoceles</em> triangle because by definition, an isoceles triangle must have two equal sides. Your given triangle has no equal sides.

6 0
2 years ago
Assuming that the sample mean carapace length is greater than 3.39 inches, what is the probability that the sample mean carapace
joja [24]

Answer:

The answer is "".

Step-by-step explanation:

Please find the complete question in the attached file.

We select a sample size n from the confidence interval with the mean \muand default \sigma, then the mean take seriously given as the straight line with a z score given by the confidence interval

\mu=3.87\\\\\sigma=2.01\\\\n=110\\\\

Using formula:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}  

The probability that perhaps the mean shells length of the sample is over 4.03 pounds is

P(X>4.03)=P(z>\frac{4.03-3.87}{\frac{2.01}{\sqrt{110}}})=P(z>0.8349)

Now, we utilize z to get the likelihood, and we use the Excel function for a more exact distribution

=\textup{NORM.S.DIST(0.8349,TRUE)}\\\\P(z

the required probability: P(z>0.8349)=1-P(z

4 0
2 years ago
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