Answer:
B) 25
Step-by-step explanation:
Given exponential function:

The growth factor between
and
is 25.
To find the growth factor between
and 
Solution:
The growth factor of an exponential function in the interval
and
is given by :

We can check this by plugging in the given points.
The growth factor between
and
would be calculated as:



Plugging in values.

(On canceling the common terms)
(Using quotient property of exponents
)

∴
Similarly the growth factor between
and
would be:



Plugging in values.

(On canceling the common terms)
(Using quotient property of exponents
)

∴
Thus, the growth factor remains the same which is =25.
Answer:
The answer is 30°
Step-by-step explanation:
I finished the test on edgen and passed
Answer:
19
Step-by-step explanation:
Follow PEMDAS
4^2 + 6 ÷ 2
16 + 6 ÷ 2
16 + 3
19
X = 10 * 3^n
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Given:
The graph of a downward parabola.
To find:
The domain and range of the graph.
Solution:
Domain is the set of x-values or input values and range is the set of y-values or output values.
The graph represents a downward parabola and domain of a downward parabola is always the set of real numbers because they are defined for all real values of x.
Domain = R
Domain = (-∞,∞)
The maximum point of a downward parabola is the vertex. The range of the downward parabola is always the set of all real number which are less than or equal to the y-coordinate of the vertex.
From the graph it is clear that the vertex of the parabola is at point (5,-4). So, value of function cannot be greater than -4.
Range = All real numbers less than or equal to -4.
Range = (-∞,-4]
Therefore, the domain of the graph is (-∞,∞) and the range of the graph is (-∞,-4].