HELPP

1 answer:

algol133 years ago

6 0

I am assuming the both cylinders have the same measure of radius. They only differ in height.

Larger Cylinder = 343 ft³
Smaller Cylinder = 125 ft³ ; height = 5 ft.

We can use proportion for this problem; a:b = c:d where ad = bc

5 ft :125 ft³ = x : 343ft³
5 ft * 343 ft³ = 125 ft³ * x
1715 ft⁴ = 125 ft³ * x
1715 ft⁴ ÷ 125 ft³ = x
13.72 ft = x height of the larger cylinder.

Cone S = 768pi cm³
Cone T = 6144pi cm³ ; height = 24 cm

24 cm : 6144 cm³ = x : 768 cm³
24 cm * 768 cm³ = 6144 cm³ * x
18,432 cm⁴ = 6144 cm³ * x
18,432 cm⁴ ÷ 6,144 cm³ = x
3 cm = x height of Cone S.

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valentinak56 [21]

Step-by-step explanation:

$\huge \: 2 \sqrt{x} .4 {x}^{ - \frac{5}{2} } \\ \\ \huge \: = 2.4 {x}^{ \frac{1}{2} } . {x}^{ - \frac{5}{2} } \\ \\ \huge \: = 8 {x}^{ \frac{1}{2} - \frac{5}{2} } \\ \\ \huge \: = 8 {x}^{ \frac{1 - 5}{2} } \\ \\ \huge \: = 8 {x}^{ - \frac{4}{2} } \\ \\ \huge \: = 8. {x}^{ - 2} \\$