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3 years ago

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Tickets to the concert where to $2.50 for adults and one dollar for students. $1200 was collected and 750 tickets were sold. Wri

te a system of linear equations that can be used to find how many adults and how many students attended how many students attended

1 answer:

erik [133]3 years ago

7 0

$2.50 (X) + $1 (Y) = $1200
X + Y = 750

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I think the answer is 14

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3 years ago

For the graph y = 1 find the slope of a line that is perpendicular to it and the slope of a line parallel to it. Explain your an

Anon25 [30]

The slope of the parallel line is 0 and the slope of the perpendicular line is undefined

<h3>How to determine the slope?</h3>

The equation is given as:

y = 1

A linear equation is represented as:

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Where:

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By comparison, we have:

m = 0

The slope of the parallel line is:

Slope = m

This gives

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1 year ago

Please help Fr pleased I’m begging you

andreyandreev [35.5K]

Answer:

y = $\frac{3}{8}$ x - 2

Step-by-step explanation:

<u>The answer to this problem is a simple plug-in of the given values into the slope-intercept formula.</u>

Slope intercept formula: y = mx + b

(m = slope)

(b = y intercept)

If the equation has a slope of m = $\frac{3}{8}$ , then the slope-intercept form would be:

y = $\frac{3}{8}$ x

If the y-intercept of an equation is (0 , -2), then the slope intercept form would be:

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2 years ago

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3 years ago

A: What are the solutions to the quadratic equation x2+9=0? B: What is the factored form of the quadratic expression x2+9? Selec

Paraphin [41]

Answer:

A. The solutions are $x=3i,\:x=-3i$ .

B. The factored form of the quadratic expression $x^2+9=(x-3i)(x+3i)$

Step-by-step explanation:

A. To find the solutions to the quadratic equation $x^2+9=0$ you must:

$\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}\\\\x^2+9-9=0-9\\\\\mathrm{Simplify}\\\\x^2=-9\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{-9},\:x=-\sqrt{-9}$

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The solutions are:

$x=3i,\:x=-3i$

B. Two expressions are equivalent to each other if they represent the same value no matter which values we choose for the variables.

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Since both terms are perfect squares, factor using the difference of squares formula

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2 years ago