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Korvikt [17]
3 years ago
7

A square is circumscribed about a circle with an 8-inch radius, as shown below. What is the area, in square inches, of the regio

n that is inside the square but outside the circle?
Choices:
16 − 64π

256−8π

64 −16 π

256 −64π

Mathematics
1 answer:
sladkih [1.3K]3 years ago
8 0

Answer:

Option 4. 256 - 64π is the correct option.

Step-by-step explanation:

In the given picture a square is circumscribed about a circle with a side = 2r

where r is the radius of the circle.

Therefore area of the square = (2r)² = 4r² = 4 × 8² = 4 × 64 = 256 in²

Now area of the circle = πr² = π × 8² = 64π in²

Now area of region that is inside the square and outside the circle =

Area of square - area of circle = (256 - 64π) in².

Therefore the answer is (256 - 64π).

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Factorise a.x3+4.a.x​
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Answer:

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factorise out a and x :

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but from general factorization:

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4 0
3 years ago
the 43rd term of an arithmetic sequence is -671 and the 52nd term is -806. find the first term and the common difference.
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Answer:

First term = -41.

Common difference = -15.

Step-by-step explanation:

nth term: an = a1 + (n - 1)d  where a = first term and d = the common difference.

-671 = a1 + (43 - 1)d

-806 = a1 +(52 - 1)d

-671  = a1 + 42d

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Subtracting ( to eliminate a1):

-671 - (-806) = 42d - 51d

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Substitute for d in the first equation:

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3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

2(-g+2)

Step-by-step explanation

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