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Natasha_Volkova [10]
3 years ago
10

1. I am a three-digit number. My tens digit is 3 more than my

Mathematics
1 answer:
Tems11 [23]3 years ago
6 0

Answer:

1. 474

2. 397

Step-by-step explanation:

1. If the three-digit number is xyz, then y = z + 3.

When rounded to the nearest ten and reduced by 320, the result is 150.  150 + 320 = 470, so x = 4.  y = 6 if z ≥ 5, and y = 7 if z < 5.

So the number is either 463 or 474.  463 doesn't round to 470, so the answer is 474.

2. If the three-digit number is xyz, then z = x + 4.  y is the largest of the three digits; since all the digits are odd, y is either 5, 7, or 9.  So z is either 5 or 7, and x is either 1 or 3.

When rounded to the nearest hundred and reduced by 100, the result is 300.  100 + 300 = 400, and y > 5, so xyz is rounded up to 400, which means x = 3.  So z = 7 and y = 9.

The answer is 397.

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<h3>What is an equation?</h3>

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The equation can be solved in the following manner,

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Learn more about Equation:

brainly.com/question/2263981

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