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AnnZ [28]
3 years ago
12

There are 9 showings of a film about endangered species at the science museum. A total of 459 people saw the film. The same numb

er of people were at each showing. About how many people were at each showing?A. 40 and 50B. 50 and 60 C. 60 and 70 D. 70 and 80
Mathematics
1 answer:
Delicious77 [7]3 years ago
7 0

Answer: B. 50 and 60

Step-by-step explanation:

Given : There are 9 showings of a film about endangered species at the science museum.

The total number of people saw the film = 459

Also, The same number of people were at each showing.

Then, the number of people were at each showing = Total people divided by Total showings

= 459 ÷ 9 = 51

Also, 50< 51 < 60  [the quotient is between 50 and 60.]

i.e.  About 50 and 60 people were at each showing .

Hence, the correct answer is B. 50 and 60.

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Jayden painted 1/6 of a wall in 2/3 hour. At this rate , how many hours will it take Jayden to paint the wall.
Anni [7]

Answer:

Step-by-step explanation:

4 0
3 years ago
Please help me with these questions , thank you​
Angelina_Jolie [31]

Answer:

1. 4x^{3} + 26x² + 4x - 48

2. 2x^{3} - 23x² + 60x - 32

3. x^{5} + 7x^{3} - 4x + 2x^{4} + 14x² - 8

4. 2x^{7} + x^{6} - 28x^{5} + 3x + 12

Step-by-step explanation:

To multiply polynomials, simply distribute whatever's outside the largest set of parenthesis, then combine like terms.

1) Distribute the parenthesis (x + 6):

x(4x² + 2x - 8)  +  6(4x² + 2x - 8)

4x^{3} + 2x² -8x  +  6(4x² + 2x -8)

4x^{3} + 2x² -8x + 24x² + 12x - 48

Combine like terms:

4x^{3} + 26x² + 4x - 48

2) Distribute the parenthesis (x - 8):

x(2x² - 7x + 4)  +  (-8)(2x² - 7x + 4)

2x^{3} - 7x² + 4x  +  (-8)(2x² - 7x + 4)

2x^{3} - 7x² + 4x  +  -16x² + 56x - 32

Combine like terms:

2x^{3} - 23x² + 60x - 32

3) Distribute the parenthesis (x + 2):

x(x^{4} + 7x² - 4)  +  2(x^{4} + 7x² - 4)

x^{5} + 7x^{3} - 4x  +  2(x^{4} + 7x² - 4)

x^{5} + 7x^{3} - 4x + 2x^{4} + 14x² - 8

No like terms to combine, so:

x^{5} + 7x^{3} - 4x + 2x^{4} + 14x² - 8

4) Distribute the parenthesis (x + 4):

x(2x^{6} - 7x^{5} + 3)  +  4(2x^{6} - 7x^{5} + 3)

2x^{7} - 7x^{6} + 3x  +  4(2x^{6} - 7x^{5} + 3)

2x^{7} - 7x^{6} + 3x + 8  x^{6} - 28x^{5} + 12

Combine like terms:

2x^{7} + x^{6} - 28x^{5} + 3x + 12

hope this helps!

8 0
2 years ago
In quadrant 11 and if x=-3/2 what is y ?
Ratling [72]
It’s 3 bbbbbbbbbbbbbbbbbbbb
5 0
3 years ago
Find the dimensions of an open rectangular box with a square base that holds 2000 cubic cm and is constructed with the least bui
Vesnalui [34]
<h3>The dimensions of the given rectangular box are:</h3><h3>L  =   15.874 cm  , B  =  15.874 cm   , H = 7.8937 cm</h3>

Step-by-step explanation:

Let us assume that the dimension of the square base = S x S

Let us assume the height of the rectangular base = H

So, the total area of the open rectangular box  

= Area of the base +  4 x ( Area of the adjacent faces)

=  S x S  +  4 ( S x H)   = S² +  4 SH   ..... (1)

Also, Area of the box  = S x S x H  =  S²H

⇒ S²H = 2000

\implies H = \frac{2000}{S^2}

Substituting the value of H in (1), we get:

A = S^2 + 4 SH =  S^2 + 4 S(\frac{2000}{S^2}) =  S^2 + (\frac{8000}{S})\\\implies A  =  S^2 + (\frac{8000}{S})

Now, to minimize the area put :

(\frac{dA}{dS} ) = 0 \implies 2S  - \frac{8000}{S^2}  = 0\\\implies S^3 = 4000\\\implies S  = 15.874 \approx 16 cm

Putting the value of S  = 15.874 cm in the value of H , we get:

\implies H = \frac{2000}{S^2}  =  \frac{2000}{(15.874)^2} = 7.8937 cm

Hence, the dimensions of the given rectangular box are:

L  =   15.874 cm

B  = 15.874 cm

H = 7.8937 cm

3 0
3 years ago
3x^2+5x_=2+_
tatiyna
IT DOES NOT MATTER YOU WILL NOT BE ABLE TO SOLVE THIS QUESTION
YOU WOULD GET 5x = 2 + 3x^2  AND YOU WOULD STILL NOT BE ABLE TO SOLVE YOU COULD GET 3x^2 = 2 + 5x AND YOU COULD NOT SOLVE.
THE REASON WHY IS BECAUSE YOU HAVE TO HAVE THE SAME X TO ADD THEM OR MINUS THEM< WHICH IN THIS CASE ONE IS REGULAR BUT THE OTHER IS SQUARED. AND ALSO THE TWO NEEDS SOMEONE TO GO WITH< BUT THE IS ONLY ONE OF HIS TYPE SO HE CAN'T.
WELCOME :/
3 0
2 years ago
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