Question

The length of a rectangle is two more than triple the width if the perimeter is 148inches find the dimensions

Answer 1

Answer:

width = 18 inches

length = 56 inches

Step-by-step explanation:

Let x = width

Let y = length

Equation 1

If length of the rectangle is 2 more than triple the width, then:

⇒ y = 3x + 2

Equation 2

Perimeter of a rectangle = 2(width + length)

If the perimeter is 148 inches, then:

⇒ 148 = 2(x + y)

Solve by substitution

Substitute Equation 1 into Equation 2 and solve for x:

⇒ 148 = 2(x + 3x + 2)

⇒ 148 = 2(4x + 2)

⇒ 148 = 2 · 4x + 2 · 2

⇒ 148 = 8x + 4

⇒ 148 - 4 = 8x + 4 - 4

⇒ 8x = 144

⇒ 8x ÷ 8 = 144 ÷ 8

⇒ x = 18

Substitute found value of x into Equation 1 and solve for y:

⇒ y = 3(18) + 2

⇒ y = 54 + 2

⇒ y = 56

Conclusion

The dimensions of the rectangle are:

• width = 18 inches
• length = 56 inches