B. The school prom committee sold presale tickets for

Mathematics

1 answer:

Ivan3 years ago

5 0

Answer:

218 students purchased tickets at the dance.

Step-by-step explanation:

Let,

x be the number of presale tickets

y be the number of tickets sold at the dance

According to given statement;

x+y=334 Eqn 1

18x+24y=7320 Eqn 2

Multiplying Eqn 1 by 18

18(x+y=334)

18x+18y=6012 Eqn 3

Subtracting Eqn 3 from Eqn 2

(18x+24y)-(18x+18y)=7320-6012

18x+24y-18x-18y=1308

6y=1308

$\frac{6y}{6}=\frac{1308}{6}\\y=218$

Therefore,

218 students purchased tickets at the dance.

You might be interested in

A shipment of 105 Otter box covers for I-phones has arrived. The total invoice (excluding tax, shipping, etc.) is $3,849.75.

bezimeni [28]

<span>3,849.75 </span>÷ 49.95 = 77 (Calculator)

Sense you would like it explained than the question is asking how many otter box Defender Covers where shipped in that price. So when you have that they want the amount of Otter Box Defenders than you divide the amount paid for the shipment with the amount of the otter box defender price.

I hope this is helpful.

3 0

3 years ago

HELP ME WITH THISSS PLZZZ!!!! ahh thank youu lol

Naddik [55]

The answer is b I think

3 0

3 years ago

The newspapers cover page is 3/8 text and photographs filled the rest if 2/5 of the text is an article about endangered species,

Papessa [141]

The fraction of text -3/8 of the cover page
From this fraction of text only 2/5 of the text is about endangered species
We are asked to find out what the fraction of the cover page is that covers endangered species
In this 2/5 of 3/8 is about endangered species
Therefore to obtain the answer we need to multiply the two fractions
2/5 * 3/8
Fraction of the cover page about endangered species is therefore = 2/5 * 3/8
= 0.15

4 0

3 years ago

Read 2 more answers

Alexis wanted to understand whether grade level had any relationship to their opinion on extending the school day. She surveyed

MakcuM [25]

Actually there is enough information to solve this problem. First, let us find the total per row and per column.

(see attached pic)

P(Grade 10 | opposed) with P(opposed | Grade 10)

P(Grade 10 | opposed) = Number in Grade 10 who are opposed / Total number of Opposed (column)

P(Grade 10 | opposed) = 13 / 41 = 0.3171

P(opposed | Grade 10) = Number in Grade 10 who are opposed / Total number in Grade 10 (row)

P(opposed | Grade 10) = 13 / 32 = 0.4063