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3 years ago

What are the six trigonometric functions of theta = 2pi ?

1 answer:

3 0

sinx=sin(π3−π)=−sin(π3)=−12.
cosx=cos(π3−π)=−cos(π3)=−√32.
tanx=−12−√32=1√3=√3.
cotx=1√3=√33.
secx=1cos=−2√3=−2√33.
cscx=1sin=−2.

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Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving

lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

$P(x=0) = ^nC_x P^x (1-P)^n^-^x$

$P(x=0) = ^5C_0 (0.4)^0 (1-0.4)^5^-^0$

$P(x=0) = ^5C_0 (0.4)^0 (0.60)^5$

$P(x=0) = 0.778$

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

$= 1 - P(X = 0)$

$= 1 - ^5C_0 (0.4)^0 * (0.6)^5$

$= 1 - 0.0778$

$= 0.9222$

c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

$^5C_0 (0.4)^0 (0.6)^5 + ^5C_1 (0.4)^1 (0.6)^4 + ^5C_2 (0.4)^2 (0.6)^3$

$= 0.6826$

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

$= 1 - [^5C_0 (0.4)^0 (0.6)^5 + ^5C_1 (0.4)^1 (0.6)^4 + ^5C_2 * (0.4)^2 (0.6)^3]$

$= 1 - 0.6826$

$= 0.3174$

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

7 0

3 years ago

Can somebody explain this to me?

hram777 [196]

First we will go to the section that lists that students that like hotdogs. 76 students out of 150 like hotdogs. Out of those 76 students, which of them like burgers?
32 students like hotdogs and burgers. 32/76 is equal to .421..., which when multiplied by 100 is equal to approximately 42.1%. We found the conditional frequency, or the column frequency. The correct answer is C.

7 0

3 years ago

which of the following ordered pairs could be placed in the table below and still have the relation qualify as a linear function

mr_godi [17]

(1,31)
Subtract 2 from x, add 8 to y

8 0

3 years ago

What is the volume of the composite figure?

saw5 [17]

volume of a sphere is 4/3 * PI * r^3

r = 6

r^3 = 6^3 = 216

4/3 * 216 = 288

Volume = 288 PI in^3

3 0

3 years ago

Heyy everyone a little halp here i kinda need it fast sorry

Studentka2010 [4]

Answer:

A) Akash (1.5m), Meera (1.52), Rahul (1.54m), Lakshmi (1.56m)

B) Lakshmi is the tallest, 1.56m tall

Step-by-step explanation:

Rahul- 1.54m

Akash- 1500mm

Meera- 152cm

Lakshmi- 1560mm

Let's start by converting all the measurements to meters.

Rahul is already in meters, so he can just stay the same.

1500mm = 1.5m

152cm = 1.52m

1560mm = 1.56m

So our new measurements are:

Rahul- 1.54m

Akash- 1.5m

Meera= 1.52m

Lakshmi= 1.56m

We can now make our conclusions.

A) Akash (1.5m), Meera (1.52), Rahul (1.54m), Lakshmi (1.56m)

B) Lakshmi is the tallest, 1.56m tall

3 0

3 years ago

Read 2 more answers