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1 year ago

Give the equation of a line that has

Mathematics

1 answer:

GenaCL600 [577]1 year ago

7 0

a. x=5

b. y=x

c. y=0

d. y=x-7

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Kira's chocolate bar is

erik [133]

The egation is 58/0.79=73
the cocoa ways 73% of the grams and 73% of 58 is 42 so the cocoa weighs 42 grams in total

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2 years ago

Which numbers are irrational? Select all that apply.

suter [353]

Option 1, 2, & 4 are irrational numbers

3 0

3 years ago

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Find the equation of this line.<br>HELP

Mumz [18]

Answer:

Step-by-step explanation:

(5,4) ; (-3, -2)

$Slope=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{-2-4}{-3-5}\\\\=\frac{-6}{-8}\\\\=\frac{3}{4}$

(5,4) & m = (3/4)

y -y1 = m(x-x1)

y - 4 = (3/4)(x - 5)

$y-4=\frac{3}{4}x-\frac{3}{4}*5\\\\y-4=\frac{3}{4}x-\frac{15}{4}\\\\y=\frac{3}{4}x-\frac{15}{4}+4\\\\y=\frac{3}{4}x-\frac{15}{4}+\frac{4*4}{1*4}\\\\y=\frac{3}{4}x-\frac{15}{4}+\frac{16}{4}\\\\y=\frac{3}{4}x+\frac{1}{4}$

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3 years ago

adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the

Zigmanuir [339]

Answer:

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$ and $\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

Step-by-step explanation:

The equation of the isotope decay is:

$\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }$

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

$\tau = \frac{5568\,years}{\ln 2}$

$\tau \approx 8032.926\,years$

The decay time is:

$t = 1315\,years + 2007\,years \pm 13\,years$ (There is no a year 0 in chronology).

$t = 3335 \pm 13\,years$

Lastly, the relative amount is estimated by direct substitution:

$\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$

$\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

4 0

2 years ago

5/2 c = 8 1/3<br> please help me

Diano4ka-milaya [45]

9514 1404 393

Answer:

3 1/3

Step-by-step explanation:

Multiply both sides by the reciprocal of the coefficient of c.

(5/2c)(2/5) = (8 1/3)(2/5)

c = (25/3)(2/5) = 50/(3·5) = 10/3

c = 10/3 = 3 1/3

3 0

3 years ago

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