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swat32
2 years ago
9

Write 1 3/4 as a decimal and as a percent

Mathematics
2 answers:
yarga [219]2 years ago
4 0

Hey there!

1 3/4

= 1 * 4 + 3 / 4

= 4 + 3 / 4

= 7 / 4

= 7 ÷ 4

= 1.75

= 1.75 * 100

= 175%

Therefore, your answer should be:

• 1.75 (as your decimal form)
• 175% (as your percentage form)


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

scoray [572]2 years ago
3 0

Answer:

Decimal: 1.75

Percentage: 175%

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Select the correct answer
AlexFokin [52]

<u>Answer:</u>

The correct answer option is C. 56.

<u>Step-by-step explanation:</u>

We are given that a group of 8 friends (5 girls and 3 boys) plans to watch a movie, but they have only 5 tickets.

We are to find the number of combinations these 5 friends could

possibly receive the tickets.

Here, we will use the concept of combination as the order of the friends is not specific.

5C5+ (5C4 * 3C1) + (5C3*3C2) + (5C2*3C3)

=1+5*3 + 10*3 +10*1 = 1+15+30+10= 56

5 0
3 years ago
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Given A(0,-4), B(0,-9), and C(-2,-5). Find the length of BC.
Ivan

Answer:

4.5

Step-by-step explanation:

B(0,-9)

C(-2,-5)

=> BC = \sqrt{(-2-0)^{2} -(-5+9)^{2} }  = 4.4721

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2 years ago
What’s the measure of
Wewaii [24]

Answer:

which angle ??

if it is DEC Then it will be 75°

4 0
3 years ago
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What is the fully factored form of 32a^3 + 12a^2?
Klio2033 [76]

<u>Answer:</u>

4a^{2} (8a + 3)

<u>Step-by-step explanation:</u>

32a^3 + 12a^2

To factorize this, start by taking the common variable out. As we have two powers for the same variable a, we can take the smaller power of a as a common to get like shown below:

32a^3 + 12a^2

a^2 (32a + 12)

Now when you have taken the variable as a common, try and take out a common number from the coefficient of a as well:

a^2 (32a + 12)

4a^2 (8a + 3)

So, the fully factored form of 32a^3 + 12a^2 is 4a^2 (8a + 3).

7 0
3 years ago
The principal of a large high school wants to know if students spend more than 1 hour doing homework per night, on average. To i
MrRissso [65]

Answer:

If we define the random variable X ="time spend by the students doign homework"

And we want to tes t is students spend more than 1 hour doing homework per night, on average (alternative hypothesis), so then the system of hypothesis for this case are:

Null hypothesis: \mu \leq 1

Alternative hypothesis: \mu >1

And they wnat to use a sample size of n = 100 and a significance level of 0.05

Step-by-step explanation:

Previous concepts

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".  

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".

Solution to the problem

If we define the random variable X ="time spend by the students doign homework"

And we want to tes t is students spend more than 1 hour doing homework per night, on average (alternative hypothesis), so then the system of hypothesis for this case are:

Null hypothesis: \mu \leq 1

Alternative hypothesis: \mu >1

And they wnat to use a sample size of n = 100 and a significance level of 0.05

7 0
3 years ago
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