Answer:
1,680 grams
Step-by-step explanation:
To solve this, we can create a proportion using this setup:
grams/people=grams/people
The recipe needs 480 grams for 4 people and x (unknown-what we are trying to find) grams for 14 people.
480 grams/4 people=x grams/14
480/4=x/14
Now, we have to solve for x-the grams needed for 14 people. To do this, we have to get x by itself. x is being divided by 14. To undo this, multiply both sides by 14, because multiplication is the opposite of division.
14(480/4)=(x/14)14
14(480/4)=x
14*120=x
1680=x
She needs 1,680 grams of couscous for 14 people.
Answer:
It will cost $256542 to prepare the field for next weeks match.
Step-by-step explanation:
The maximum dimensions of a field according to FIFA rules is 110 m by 75 m.
So, the maximum area of a field is (110 × 75) = 8250 square meters.
Now, 1 square meters is equivalent to 1.196 square yards.
So, the maximum area of a field is (8350 × 1.196) = 9867 square yards.
Now, given that it costs to make ready each square yard of a full-size FIFA field, $26 before each game.
Therefore, it will cost $(26 × 9867) = $256542 to prepare the field for next week's match. (Answer)
Answer:
114, and 115
Step-by-step explanation:
114+115 = 229
Answer:

= 7.071067812
Step-by-step explanation:
hope this helps
Answer:
see explaination
Step-by-step explanation:
Using the formulla that
sum of terms number of terms sample mean -
Gives the sample mean as \mu=17.954
Now varaince is given by
s^2=\frac{1}{50-1}\sum_{i=1}^{49}(x_i-19.954)^2=9.97
and the standard deviation is s=\sqrt{9.97}=3.16
b) The standard error is given by
\frac{s}{\sqrt{n-1}}=\frac{3.16}{\sqrt{49}}=0.45
c) For the given data we have the least number in the sample is 12.0 and the greatest number in the sample is 24.1
Q_1=15.83, \mathrm{Median}=17.55 and Q_3=19.88
d) Since the interquartile range is Q_3-Q_1=19.88-15.83=4.05
Now the outlier is a number which is greater than 19.88+1.5(4.05)=25.96
or a number which is less than 15.83-1.5(4.05)=9.76
As there is no such number so the given sample has no outliers