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gayaneshka [121]
3 years ago
5

Is the following Inductive Generalization strong or weak? Apply and explain the three checks: 1. Is the appropriate group sample

d? 2. Is the sample truly random? 3. Is the sample adequate in number? Then give your verdict: strong or weak.
Oxytocin seems to make people more inclined to trust strangers with their cash. In a game in which 58 volunteers could invest money with anonymous trustees, economist Ernst Fehr of the University of Zurich and his colleagues dosed half the subjects with a whiff of oxytocin while the others received an inert placebo nose spray (but were told it was a real drug). After investors who sniffed the actual oxytocin were twice as likely to invest all their funds.
Mathematics
1 answer:
arsen [322]3 years ago
5 0

Answer:

For the reasons mentioned in the explanation section, it is indeed a weak generalization:  

Step-by-step explanation:

  • No, there is not enough data provided on certain subjects' age, socioeconomic status, etc. that may have influenced the investing decision.
  • No, the survey isn't random, the study is irregular because each has a fair probability of expressing their true beliefs, here in this query it's written they've been told individuals are given actual medication, which may have contributed to the Hawthorne studies giving incorrect outcomes.
  • No, the amount isn't sufficient mostly on the premise of 28 subject areas with be provided oxytocin, and therefore only one test being performed should we not be able to determine the results to implement for certain persons including billions of populace, it would be a hurried generalization.
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gregori [183]

Answer:

  (a) true

  (b) true

  (c) false; {y = x, t < 1; y = 2x, t ≥ 1}

  (d) false; y = 200x for .005 < |x| < 1

Step-by-step explanation:

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This equation matches the form of a function periodic with period 2T.

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(b) A system being linear means the output for the sum of two inputs is the sum of the outputs from the separate inputs:

  s(a) +s(b) = s(a+b) . . . . definition of linear function

Then if a=b, you have

  2s(a) = s(2a)

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(c) The output from a time-shifted input will only be the time-shifted output of the unshifted input if the system is time-invariant. The problem conditions here don't require that. A system can be "linear continuous time" and still be time-varying.

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(d) A restriction on an input magnitude does not mean the same restriction applies to the output magnitude. The system may have gain, for example.

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