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2 years ago

10

A common approach to keeping a record of each customer's account receivable is to use a subsidiary accounts receivable ledger.a.

Trueb. False

1 answer:

Phantasy [73]2 years ago

4 0

Answer:

True

Step-by-step explanation:

The given statement is true as a common approach to keeping a record of each customer's account receivable is to use a subsidiary accounts receivable ledger. An account's receivable subsidiary ledger is an accounting ledger that shows the transaction and payment history of each customer to whom the business extends credit.

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A local company rents a moving truck for $750 plus $0.59 per mile driven over 1000 mi. What is the maximum number of miles the t

Katen [24]

The maximum number of miles the truck can be driven so that the rental cost is at most $\$1000$ is $\boxed{1423{\text{ miles}}}.$

Further explanation:

Given:

A local company rents a moving truck for $\$ 750.$

Rent per mile is $\$ 0.59$ if the truck moves more than 1000 miles.

Explanation:

The rental cost of the truck is $\$ 750$ if he drove less than 1000 miles.

${\text{Cost}} = \$ 750{\text{ }}x \leqslant 1000$

The rental cost of the truck can be expressed as follows,

${\text{Cost}} = 750 + 0.59x{\text{ }}x > 1000$

The rental cost is at most $\$1000.$

$750 + 0.59x \leqslant 1000$

The maximum number of miles can be obtained as follows,

$\begin{aligned}0.59x &\leqslant 1000 - 750\\0.59x &\leqslant 250\\x &\leqslant \frac{{250}}{{0.59}}\\x &\leqslant 423.7\\\end{aligned}$

The maximum number of miles can be obtained as follows,

$\begin{aligned}{\text{Maximum miles}} &= 1000 + 423\\&= 1423 \\\end{aligned}$

The maximum number of miles the truck can be driven so that the rental cost is at most $\$1000$ is $\boxed{1423{\text{ miles}}}.$

Learn more:

Learn more about inverse of the function brainly.com/question/1632445.
Learn more about equation of circle brainly.com/question/1506955.
Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Linear inequality

Keywords: local company, rents, moving, truck, $750, $0.59, maximum, 1000 miles, $1000, at most, at least, number of miles, rental cost, driven over

3 0

3 years ago

Read 2 more answers

Loretta’s income last year was $81,300. She made $56,800 at her salaried job and had additional passive income. If Loretta earne

adell [148]

Answer:

The answer is $2041.67 approx.

Step-by-step explanation:

Loretta’s income last year was $81,300.

Amount made in salary = $56,800

So, additional passive income is = $81300-56800=24500$ dollars

Given that Loretta earned the same amount of passive income each month for the entire year.

So, her per month passive earning was = $\frac{24500}{12}=2041.67$ dollars

Therefore, the answer is $2041.67 approx.

3 0

2 years ago

HELP ME PLS I NEED THIS !!!!

ZanzabumX [31]

Answer:

Go google the answer

Step-by-step explanation:

3 0

3 years ago

The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

8 0

2 years ago

A grab bag contains 12 packages worth $.70 each, 15 packages $.40 cents each, and 25 packages worth $.30 each. what is the expec

Salsk061 [2.6K]

The expected value of the discrete distribution, if you have to pay $.50 to pick one package at random, is of -$0.08.

<h3>What is the mean of a discrete distribution?</h3>

The expected value of a discrete distribution is given by the <u>sum of each outcome multiplied by it's respective probability</u>.

For this problem, considering the cost of $0.5, the distribution is given as follows:

P(X = 0.2) = 12/(12 + 15 + 23) = 12/50 = 0.24.

P(X = -0.1) = 15/(12 + 15 + 23) = 15/50 = 0.3.

P(X = -0.2) = 23/(12 + 15 + 23) = 23/50 = 0.46.

Hence the expected value is given by:

E(X) = 0.2 x 0.24 - 0.3 x 0.1 - 0.2 x 0.46 = -$0.08.

More can be learned about the expected value of a discrete distribution at brainly.com/question/13008984

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8 0

1 year ago