Yes, substitute a=2.
14 - 4 + 6 - 6 = -2
8 - 10 = -2
Answer: Median= 91; 8th quiz score=86
Step-by-step explanation: The sum of the scores is 8×92=736. Subtract the 6 given scores and then a 100 for the seventh quiz to find the score she got on the 8th quiz, this is an 86. Now that you have all the scores, arrange them all in the least to greatest order and find the average of the middle two numbers (median), which is 91!
Answer:
There are 15 letters, but if the two A's must always be together, that's the same as if they're just one letter, so our "base count" is 14! ; note that this way of counting means that we also don't need to worry about compensating for "double counting" identical permutations due to transposition of those A's, because we don't "count" both transpositions. However, that counting does "double count" equivalent permutations due to having two O's, two N's, and two T's, so we do need to compensate for that. Therefore the final answer is 14!/(23)=10,897,286,400
If in a number plate two different alphabets need to be selected then there are 650 such number plates that can be formed in such a way that the alphabets come in increasing order.
Given that a number plate can be formed using 2 alphabets which must come in increasing order.
We are required to find the number of plates that can be formed.
Number of total alphabets=26.
The number of plates will be equal to the number of ways in which two alphabets can be arranged.
Combination is the number of ways in which some combinations can be formed. It is expressed as n
=n!/r!(n-r)!
Number of license plates=26
*25
=26*25
=650 plates
Hence If in a number plate two different alphabets need to be selected then there are 650 such number plates that can be formed in such a way that the alphabets come in increasing order.
Learn more about combinations at brainly.com/question/11732255
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