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2 years ago

Order the numbers from least to greatest -4 -4.35 -4.9 -5 and -4.3

Mathematics

1 answer:

Natalija [7]2 years ago

3 0

Answer:

-5,-4.9,-4.35,-4.3,-4

Step-by-step explanation:

Hope this helps :)

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A bus travels at a constant speed. The following table shows the distance the bus travels (in kilometers) over a period of time

Olegator [25]

Answer:

315 km

Step-by-step explanation:

If the bus travels at constant speed, then the slope of the distance versus time graph can be calculated by using any two points from this table.

Let's use the points (0.5, 42) and (4.5, 378):

as we move from the first point to the second, t increases by 4 and y increases by 336. Thus, the slope of this graph is

m = rise / run = 336 km / 4 hr = 84 km/hr

then distance traveled = speed times time, or

distance traveled = (84 km/hr)t, where t is the elapsed time.

In 6 hours the bus would travel

( 84 km/hr )(6 hr) = 504 km, or approx. 315 mi

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3 years ago

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Which expression is equivalent to 2g53 4h23

romanna [79]

Answer:

girl are u crazy

Step-by-step explanation:

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3 years ago

Find the quotient: 8,358 ÷ 27 = ________. 309 r 15 309 r 26 310 r 15 310 r 26

Rus_ich [418]

Answer:

the answer is 309 r 15

Step-by-step explanation:

309 × 27 is 8343 and your left with 15

7 0

3 years ago

Please help!! I will give correct answer brainelest! 15 points!

4vir4ik [10]

Minimum is 40

First quartile is 43

Median is 61

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3 years ago

Ann is adding water to a swimming pool at a constant rate. The table below shows the amount of water in the pool after different

N76 [4]

Answer:

(a) As time increases, the amount of water in the pool increases.

11 gallons per minute

(b) 65 gallons

Step-by-step explanation:

From inspection of the table, we can see that as time increases, the amount of water in the pool increases.

We are told that Ann adds water at a constant rate. Therefore, this can be modeled as a linear function.

The rate at which the water is increasing is the rate of change (which is also the slope of a linear function).

Choose 2 ordered pairs from the table:

$\textsf{let}\:(x_1,y_1)=(8, 153)$

$\textsf{let}\:(x_2,y_2)=(12,197)$

Input these into the slope formula:

$\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{197-153}{12-8}=\dfrac{44}{4}=11$

Therefore, the rate at which the water in the pool is increasing is:

11 gallons per minute

To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:

$y-y_1=m(x-x_1)$

$\implies y-153=11(x-8)$

$\implies y-153=11x-88$

$\implies y=11x-88+153$

$\implies y=11x+65$

When Ann had added no water, x = 0. Therefore,

$y=11(0)+65$

$y=65$

So there was 65 gallons of water in the pool before Ann starting adding water.

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2 years ago

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