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Feliz [49]
2 years ago
5

16. What is the area of the shaded region in terms of Tr? [20 points]

Mathematics
1 answer:
tangare [24]2 years ago
6 0
Area of the circle outside
= πr2
= π(5)2
=25 π

Area of the bigger circle inside
= π x(3)2
= 9 π
Area of the smaller circle inside
= π x (2)2
= 4 π

Area of shaded region
= 25π - 9π - 4π
= 12π square unit
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Tonya has 39 packages. Each package weighs 6 pounds. Choose the best estimate of the total weight of the packages.
Sidana [21]

Step-by-step explanation:

If were estimating, 39 is pretty close to 40 and 40x6 is 240 pounds. if we are getting exact about it, then 234 pounds

5 0
2 years ago
Marco bought $30 worth of football cards. If he bought 12 packs of cards, how much does each pack of cards cost?
Mandarinka [93]

Answer:

2.5

Step-by-step explanation:

30/12=2.5

7 0
2 years ago
Read 2 more answers
Algebra 1 Grade 9
Whitepunk [10]

You are describing where I live only that temperature is a bit low. I'm sorry to say it is neither one.

t_daily = t_average +/- 5

The highest temperature would be

t_daily = t_average + 5

t_daily = 1 + 5

t_daily = 6

================

The Lowest temperature would be

t_daily = t_average - 5

t_daily = 1 - 5

t_daily = - 4

Sounds about right for December.

6 0
3 years ago
Help me fast I need please
ale4655 [162]

Answer:

2/9

Step-by-step explanation:

Since there are 18 total eggs (cracked, white, brown) we can say that the denominator will be 18.

There are 8 white eggs, and when half of those are cracked there will be 4 uncracked and 4 cracked, so 4/18.

Simplify 4/18 to 2/9 and there is your answer.

4 0
2 years ago
Please please help me out
Inessa [10]

Answer:

26.6 m

Step-by-step explanation:

Given the figures are similar

linear ratio = a : b

area ratio = a² : b²

here

area ratio = 16 : 25, then

linear ratio = 4 : 5 ( square root of both area ratio parts )

let the perimeter of the larger figure be x, then by proportion

\frac{4}{21.3} = \frac{5}{x} ( cross- multiply )

4x = 106.5 ( divide both sides by 4 )

x ≈ 26.6

Hence perimeter of larger figure is approximately 26.6 m

3 0
3 years ago
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