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3 years ago

How do you do it? Or how do you solve it? Can you give me the answer so I could understand better?

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

6 0

There is nothing to solve, at least for me there isn't, should there be a picture?

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Please help hard math good points

Elis [28]

Try B...because the points meet at a intersection

4 0

3 years ago

Plzzzzz help me with this

ehidna [41]

Answer:

We conclude that we must add 4² or 16 to complete the square.

Hence, option C i.e. 16 is the correct answer.

Step-by-step explanation:

We know that the perfect square formula is

(a + b)² = a² + b² + 2ab

Given the equation

$x^2+8x$

Let us add 4² or 16 in the equation

$x^2+8x+4^2$

$x^2+\:2\left(1\right)\left(4\right)x+4^2$

as (a + b)² = a² + b² + 2ab, so

$x^2+8x+4^2=\left(x+4\right)^2$

Therefore, we conclude that we must add 4² or 16 to complete the square.

Hence, option C i.e. 16 is the correct answer.

4 0

3 years ago

Read 2 more answers

A square has an area that is less than 100 m. What is a reasonable range for the graph of the

WITCHER [35]

1-9 I’m pretty sure but idk

7 0

3 years ago

Using f(x) = 8x + 5 and g(x) = 7x - 2, find:g(f(6))

iren2701 [21]

Answer:

369

Step-by-step explanation:

g(f(x)) simply means to put the whole expression of function f(x) into the place of "x" in g(x).

and to find the functional value for a specific x we just need to calculate functional value for f(x) and use that result as input for g(x).

f(6) = 8×6 + 5 = 48 + 5 = 53

and now

g(53) = 7×53 - 2 = 371 - 2 = 369

to check we do the general functional substitution :

g(f(x)) = 7×(8x+5) - 2 = 56x + 35 - 2 = 56x + 33

g(f(6)) = 56×6 + 33 = 336 + 33 = 369

correct

5 0

3 years ago

Para reunir dinero para su gira de estudios , los alumnos de un curso deciden vender números de una rifa que se encuentran numer

QveST [7]

Respuesta:

0.53

Explicación:

Para calcular la posibilidad del evento A: "ganar la rifa comprando todos los números múltiplos de 3 o 5", debemos usar la siguiente fórmula.

P(A) = casos favorables / casos posibles

Evaluemos primero todos los casos que son múltiplos de 3, entre 1 y 100: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99. En total son 33.

Ahora, evaluemos todos los casos que son múltiplos de 3, entre 1 y 100: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100. En total son 20.

El número total de casos favorables es 33 + 20 = 53.

El número de casos posibles es el total de números de 1 a 100, es decir 100.

Luego P(A) = 53/100 = 0.53.

7 0

3 years ago