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Salsk061 [2.6K]
3 years ago
6

A net force acting on a 5.0 kg box produces an acceleration of 4.2 m/s2. What

Mathematics
2 answers:
liq [111]3 years ago
6 0

Answer:

14 N

Step-by-step explanation:

Let the mass of the box be m.

F = ma → F = 5 x 4.2 = 21 N

When mass = 2.8 kg, let the acceleration is a. For same force:

=> 21 = a x 2.8

=> 21/2.8 = a

=> 7.5 m/s² = a

Mashcka [7]3 years ago
3 0

Answer:

7.5M/s^2

Step-by-step explanation:

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Solve the equation 29 - (x+8) = 6x - 7
max2010maxim [7]
First step you should do is s<span>implify both sides of your equation:
</span>29-(x+8)=6x-7
Distribute the Negative Sign:
29+-1(x+8)=6x-7
29+-1x+(-1)(8)=6x-7
29+-x+-8=6x-7
29+-x+-8=6x+-7
<span>Combine Like Terms:
</span>(-x)+(29+-8)=6x-7
-x+21=6x-7
<span>Subtract 6x from both sides:
</span>-x+21-6x=6x-7-6x
-7x+21=-7
<span>Subtract 21 from both sides:
</span>-7x+21-21=-7-21 
-7x=-28 
<span>Divide both sides by -7:
</span>-7x/-7 = -28/-7
And now your answer should be:
x=4
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Good luck~ Sans
6 0
3 years ago
I NEED HELP WITH THIS ASAP <br> I WILL GIVE BRAINLIEST
natita [175]

Answer

x=100

y= 4.5

x=6

y= 1.87

Step-by-step explanation:

4 0
3 years ago
What is 7/56 simplified
Neko [114]

Answer:

1/8  

Step-by-step explanation:

BOOM!

8 0
3 years ago
Read 2 more answers
Tyler made a scale drawing of a 24 ft long boat. In his drawing, the boat was 6 inches. The scale that Tyler used for his drawin
defon

Answer:

In Tyler scale, 1 inch equals 4 ft.

Step-by-step explanation:

Giving the following information:

Tyler made a scale drawing of a 24 ft longboat. In his drawing, the boat was 6 inches.

<u>We know that 1 ft is 12 inches. Therefore, 24 ft:</u>

24*12= 288 inches

<u>Now, we have to determine the scale that Tyler used.</u>

<u></u>

1 Tyler inch= 288/6= 48 inches

In ft:

1 Tyler inch= 48/12= 4 ft

In Tyler scale, 1 inch equals 4 ft.

3 0
3 years ago
Suppose that $9500 is placed in an account that pays 8% interest compounded each year.
Blababa [14]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$9500\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{each year, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}


\bf A=9500\left(1+\frac{0.08}{1}\right)^{1\cdot 1}\implies A=9500(1.08)\implies \boxed{A=10260} \\\\\\ \stackrel{\textit{after 2 years, t = 2}}{A=9500\left(1+\frac{0.08}{1}\right)^{1\cdot 2}}\implies A=9500(1.08)^2\implies \boxed{A=11080.8}

6 0
3 years ago
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