Question

Newton’s Law of Cooling expresses the relationship between the temperature of a cooling object y and the time t elapsed since cooling began, in minutes. This relationship is given by y=ae where c is the temperature of the medium surrounding the cooling object, a is the difference between the initial temperature of the object and the surrounding temperature, and k is a constant related to the cooling object. -The initial temperature of a liquid is When it is removed from the heat, the temperature in the room is . For this object, Use Newton’s Law of Cooling to find the temperature of the liquid after 15 minutes.

Answer 1

Answer:

The correct answer is 78.7°F

Step-by-step explanation:

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Answer 2

Answer:

79 °F

Step-by-step explanation:

Newton’s Law of Cooling:

$y = ae^{-kt} + c$

Data

• The initial temperature of a liquid is 160 °F

• The temperature in the room (c) is 76 °F

• Then a = 160 - 76 = 84 °F

• k = 0.23

• t = 15 minutes

Replacing into the equation:

$y = 84e^{-0.23 \times 15} + 76$

y = 79 °F