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netineya [11]
3 years ago
7

One of the solutions to x^2– 2x – 15 = 0 is x = -3. What is the other solution?

Mathematics
1 answer:
guajiro [1.7K]3 years ago
3 0

Answer:x=5

Step-by-step explanation: x^2−2x−15=0

(x−5)=0                                                                                                                      x−5=0                                                                                                                             x=5                                                                                                                                                                                                              

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Read 2 more answers
I.The difference between two numbers is 5. Their product is 36.
faust18 [17]
Equ 1: X-Y=5
equ 2: x∗y=36
from Equ 1
     X=5+Y------equ 3
substitute x=5+y in equ 2
(5+y)∗y=36
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factorize by substitution
(y^2+9y)-(4y-36)=0
y(y+9)-4(y+9)=0
(y-4)(y+9)=0
y=4 or y=-9....

substitute y=4 or -9 in equ 1
x-4=5
x=5+4
x=9 OR

x-(-9)=5
x+9=5
x=5-9
x=-4

since -4∗-9=36
therefore y=-9 and x=-4



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