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3 years ago

Draw graphs of the following lines: The line through the origin having a slope of 1/4

Mathematics

1 answer:

KengaRu [80]3 years ago

4 0

I think its 1 on the graph correct me if im wrong

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35. V112 + V63 How do I solve this please

konstantin123 [22]

Answer: 175V

Step-by-step explanation:

V112+V63=112v+63V

Add them together because the terms are like terms. Therfore, 112V+63V=175V

4 0

3 years ago

The value of a dirt bike decreases by 15% each year. If you purchased this dirt bike today for $500, to the nearest dollar how m

ANTONII [103]

Right now the dirt bike is worth $500. Next year it will be worth 15% less, or 85% of the current value (because currently it's at 100%, so you would subtract the 15%). To find 85% of the dirt bike's value, you would take $500 and multiply by 85% (or 0.85). This would give you $425 after 1 year. You'd take $425 and multiply that by 85% for the next year, and continue until you reached 5 years of the value decreasing. Does this help?

6 0

3 years ago

Read 2 more answers

Simplify 14z+12y3+10y3+7y3

Alona [7]

Answer:

14z+29y^3

Step-by-step explanation:

14z+12y^3+10y^3+7y^3

Combine like terms

14z+29y^3

4 0

3 years ago

Read 2 more answers

Pls help me one through 12

ale4655 [162]

It is just 18 :)It is just 18 :)

7 0

3 years ago

Read 2 more answers

the equation of a circle in general form is x squared + y squared + 20x + 12 y + 15 equals 0what is the equation of the circle i

Marrrta [24]

Answer: $(x+10)^2+(y+6)^2=121$

Step-by-step explanation:

The equation of a circle in the general form is:

$ax^{2}+by^2+cx+dy+e=0$

The equaton of a circle in standard form is:

$(x-h)^2+(y-k)^2=r^2$

Where the center is at (h, k) and r is the radius

To write the equation of a circle from general form to standard form, you must complete the squaare, as you can see below:

1- Given the equation in general form:

$x^{2}+y^2+20x+12y+15=0$

2- Complete the square:

-Group the like terms and move the constant to the other side.

- Complete the square on the left side of the equation.

- Add the same value to the other side.

Then you obtain:

$(x^{2}+20x)+(y^2+12y)=-15\\(x^2+20x+(\frac{20}{2})^2)+(y^2+12y+(\frac{12}{2})^2)=-15+(\frac{20}{2})^2+(\frac{12}{2})^2\\\\(x+10)^2+(y+6)^2=-15+100+36\\(x+10)^2+(y+6)^2=121$

4 0

3 years ago