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3 years ago

3, 2.7 - 3, 1.4 (these are numbers on a x,y graph.)

Mathematics

1 answer:

Serggg [28]3 years ago

6 0

I would help but you don’t have graph:(

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At a camp, kids can choose swimming, art, or music. 40 kids choose swimming, 16 choose art, and 24 choose music. What is the rat

Anna [14]

the ratio would be as follows

40:16

5:2

Worded there are five kids who choose to swim to every 2 kids that choose art.

this could also be written as a fraction 40/16 = 5/2

7 0

3 years ago

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Find an equation in standard form for the hyperbola with vertices at (0, ±3) and foci at (0, ±7)

Nitella [24]

The equation of a hyperbola is:

(x – h)^2 / a^2 - (y – k)^2 / b^2 = 1

So what we have to do is to look for the values of the variables:

For the given hyperbola : center (h, k) = (0, 0)
a = 3(distance from center to vertices)
a^2 = 9

c = 7 (distance from center to vertices; given from the foci)
c^2 = 49

By the hypotenuse formula:
c^2 = a^2 + b^2
b^2 = c^2 - a^2

b^2 = 49 – 9

b^2 = 40

Therefore the equation of the hyperbola is:

(x^2 / 9) – (y^2 / 40) = 1

5 0

3 years ago

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Plz answer the question

Bumek [7]

24 were of the questione were correct

3 0

3 years ago

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What are all the cheat codes for shreadsauce

Arisa [49]

Answer:

superspin

lowgravity

dontcrash

Step-by-step explanation:

thats all they have so far

7 0

3 years ago

Does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?

stiv31 [10]

Given equation of the Circle is ,

$\sf\implies x^2 + y^2 = 25$

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

$\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2$

Here we can say that ,

• Radius = 5 units

• Centre = (0,0)

Finding distance between the two points :-

$\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }$

Here we can see that the distance of point from centre is less than the radius.

Hence the point lies within the circle .

5 0

3 years ago

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