Answer:

Step-by-step explanation:
The firm tests 75 parts, and finds that 0.25 of them are notusable
n = 75
x = 0.25 \times 75 = 18.75≈19



Confidence level = 95%
So, Z_\alpha at 95% = 1.96
Formula of confidence interval of one sample proportion:


Confidence interval 
Answer:
x= −2 or x=3
Step-by-step explanation:
Answer:
8(3x-5)
8 is the GCF of 24 and 40 so you write 8 and in brackets you put your terms after you divide by 8 so you get 3x and -5 so it is written as 8(3x-5)
-30m^3-3 here is your answer
Answer:
C) 61
Step-by-step explanation: