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eduard
3 years ago
12

What is the slope of the line on the graph?

Mathematics
1 answer:
bearhunter [10]3 years ago
7 0
The answer is c…the slope is 2
You might be interested in
Calculate the circumference of a circle when the diameter is 5cm. Give your answer to 2
FrozenT [24]

Answer:15.70

Step-by-step explanation:The formula for the circumference is 2πr. Plug-in the number provided into the formula, since diameter is double the radius you just divide the 5 by 2 to get 2.5.

So, 2π2.5=15.70

2 time π =6.28

6.28 time 2.5= 15.70

7 0
3 years ago
How much simple interest does 600 make in 3 years at7%per annum<br>​
mihalych1998 [28]

Answer:

126

Step-by-step explanation:

I = prt

I = (600)(0.07)(3)

I = 126

Answer: 126

7 0
3 years ago
What fraction of her team's total points did Cynthia score?
Nataly_w [17]

Answer: 5/6

Step-by-step explanation:

because if you get velocity and multiply it by the term which is 5/12 you half the denominator.

7 0
3 years ago
The volume of a cylinder can is 1.54 litre and area of base is 77cm^2 Find its height​
goblinko [34]

Answer:

The height is 20 cm.

Step-by-step explanation:

First, we have to know that the volume formula is V = πr²h and the base area of cylinder is a circle. So we can let πr² be 77 cm² . Then we have to substitute the following values into the formula :

v = 1.54 \: l

v = 1540 \:  {cm}^{3}

v = \pi \times  {r}^{2}  \times h

Let πr² be 77,

Let v be 1540,

1540 = 77 \times h

77h = 1540

h = 1540  \div 77

h = 20 \: cm

5 0
3 years ago
Show that there do not exist scalars c1, c2, and c3 such that c1(1, 0, 1, 0) + c2(1, 0, -2, 1) + c3(2, 0, 1, 2) = (1, -2, 2, 3)
Aloiza [94]

Write the system in augmented-matrix form:

c_1(1,0,1,0)+c_2(1,0,-2,1)+c_3(2,0,1,2)=(1,-2,2,3)

\iff\left[\begin{array}{ccc|c}1&1&2&1\\0&0&0&-2\\1&-2&1&2\\0&1&2&3\end{array}\right]

Row reduce this matrix:

  • Add -1(row 1) to row 3:

\left[\begin{array}{ccc|c}1&1&2&1\\0&0&0&-2\\0&-3&-1&1\\0&1&2&3\end{array}\right]

  • Add 3(row 4) to row 3:

\left[\begin{array}{ccc|c}1&1&2&1\\0&0&0&-2\\0&0&5&10\\0&1&2&3\end{array}\right]

  • Multiply row 3 by 1/5:

\left[\begin{array}{ccc|c}1&1&2&1\\0&0&0&-2\\0&0&1&2\\0&1&2&3\end{array}\right]

  • Add -2(row 3) to row 4:

\left[\begin{array}{ccc|c}1&1&2&1\\0&0&0&-2\\0&0&1&2\\0&1&0&-1\end{array}\right]

  • Add -2(row 3) and -1(row 4) to row 1:

\left[\begin{array}{ccc|c}1&0&0&-2\\0&0&0&-2\\0&0&1&2\\0&1&0&-1\end{array}\right]

This matrix tells us that c_1=-2, c_2=-1, and c_3=2, but clearly 0c_1+0c_2+0c_3=0\neq-2, so there is no solution.

3 0
3 years ago
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