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kkurt [141]
3 years ago
8

136.422what is the 3 value

Mathematics
1 answer:
svp [43]3 years ago
3 0
It's in the ten thousandth place
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The graph depicts the growth and costs using of line segment use the midpoint formula to approximate the cost during the year 19
marysya [2.9K]

Answer:

The approximate cost during the year 1987 was $7,533

Step-by-step explanation:

The complete question in the attached figure

we have

y -----> is the cost in dollars

x -----> is the year

Looking at the graph we have the points

(1983,5,047) and (1991, 10,019)

To determine the cost in the year 1987, find out the midpoint between the two given points

The formula to calculate the midpoint between two points is equal to

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

substitute the values

M=(\frac{1983+1991}{2},\frac{5,047+10,019}{2})

M=(1987,7,533)

therefore

The approximate cost during the year 1987 was $7,533

7 0
3 years ago
PLSSS HELPPP! I will give brainliest and 11 points!!
WARRIOR [948]

Answer:

B:

4 units right and six units up

4 0
3 years ago
Read 2 more answers
Please help me solve this, I will give you Brainliest. !
Brrunno [24]

\frac{8 + x}{2}

6 0
3 years ago
Read 2 more answers
What is the solution to the system of equations?
Dovator [93]

Answer:

<h2>(-10, 2, 6)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}x+3y+2z=8&(1)\\3x+y+3z=-10&(2)\\-2x-2y-z=10&(3)\end{array}\right\qquad\text{subtract both sides of the equations (1) from (2)}\\\\\underline{-\left\{\begin{array}{ccc}3x+y+3z=-10\\x+3y+2z=8\end{array}\right }\\.\qquad2x-2y+z=-18\qquad(4)\qquad\text{add both sides of the equations (3) and (4)}\\\\\underline{+\left\{\begin{array}{ccc}-2x-2y-z=10\\2x-2y+z=-18\end{array}\right}\\.\qquad-4y=-8\qquad\text{divide both sides by (-4)}\\.\qquad\qquad y=2\qquad\text{put the value of y to (1) and (3)}

\left\{\begin{array}{ccc}x+3(2)+2z=8\\-2x-2(2)-z=10\end{array}\right\\\left\{\begin{array}{ccc}x+6+2z=8&\text{subtract 6 from both sides}\\-2x-4-z=10&\text{add 4 to both sides}\end{array}\right\\\left\{\begin{array}{ccc}x+2z=2&\text{multiply both sides by 2}\\-2x-z=14\end{array}\right\\\underline{+\left\{\begin{array}{ccc}2x+4z=4\\-2x-z=14\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad3z=18\qquad\text{divide both sides by 3}\\.\qquad\qquad z=6\qquad\text{put the value of z to the first equation}

x+2(6)=2\\x+12=2\qquad\text{subtract 10 from both sides}\\x=-10

4 0
3 years ago
Your tea her will grade your response 4-8 to ensure you receive proper credit
svlad2 [7]

Answer:

k = 73

Step-by-step explanation:

The sum of all the angles in a triangle is  180  degrees.

62 °  +  k +  45 °  =  180

Solve the equation for k

Add  62 °  and  45 °

k +  107  =  180

Move all terms not containing  C  to the right side of the equation.

Subtract  107  from both sides of the equation.

k  =  180  −  107

Subtract

k  =  73

4 0
3 years ago
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