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Alik [6]
3 years ago
6

Solve for x X+5>4 Enter your answer as an inequality. In the box

Mathematics
1 answer:
Arisa [49]3 years ago
4 0
  • Answer:

x > - 1

x ∈ ( - 1 ; + oo)

  • Step-by-step explanation:

Hi there !

x + 5 > 4

x > 4 - 5

x > - 1

x ∈ ( - 1 ; + oo)

Good luck !

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I need help on 24 please
charle [14.2K]
F. 24, this is because if you split the bigger square in half you’ll get 6 and perimeter is the addition of all sides. So 6+6+6+6=24
4 0
3 years ago
Help please! Ty!! ----
Tresset [83]

Answer:

5 4/9

Step-by-step explanation:

9 x 5 + 4= 5 4/9

BRAINLIEST PLZAESE

3 0
3 years ago
How would you do this???
Kobotan [32]

Answer:

8.3 L/s

Step-by-step explanation:

To find the answer you need to find the slope also known as the rate of change. When you find slope it is always change in y over change in x.

\frac{399-150}{40-10}

Then simplify

\frac{249}{30}

Then divide to get your slope/average rate of change

\frac{249}{30} = 8.3

6 0
4 years ago
By hiring 45 new employees, a department store increased its help by 18% during the Christmas season. How many employees did the
bagirrra123 [75]
Hi!

We can set up a proportion then cross multiply to solve this.

\frac{45}{x}  \frac{18}{100}

45 x 100 = 4500
4500/18 = 250

The answer is 250

Hope this helps! :)
7 0
3 years ago
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
FromTheMoon [43]

Answer:

The Taylor series is \ln(x) = \ln 3 + \sum_{n=1}^{\infty} (-1)^{n+1} \frac{(x-3)^n}{3^n n}.

The radius of convergence is R=3.

Step-by-step explanation:

<em>The Taylor expansion.</em>

Recall that as we want the Taylor series centered at a=3 its expression is given in powers of (x-3). With this in mind we need to do some transformations with the goal to obtain the asked Taylor series from the Taylor expansion of \ln(1+x).

Then,

\ln(x) = \ln(x-3+3) = \ln(3(\frac{x-3}{3} + 1 )) = \ln 3 + \ln(1 + \frac{x-3}{3}).

Now, in order to make a more compact notation write \frac{x-3}{3}=y. Thus, the above expression becomes

\ln(x) = \ln 3 + \ln(1+y).

Notice that, if x is very close from 3, then y is very close from 0. Then, we can use the Taylor expansion of the logarithm. Hence,  

\ln(x) = \ln 3 + \ln(1+y) = \ln 3 + \sum_{n=1}^{\infty} (-1)^{n+1} \frac{y^n}{n}.

Now, substitute \frac{x-3}{3}=y in the previous equality. Thus,

\ln(x) = \ln 3 + \sum_{n=1}^{\infty} (-1)^{n+1} \frac{(x-3)^n}{3^n n}.

<em>Radius of convergence.</em>

We find the radius of convergence with the Cauchy-Hadamard formula:

R^{-1} = \lim_{n\rightarrow\infty} \sqrt[n]{|a_n|},

Where a_n stands for the coefficients of the Taylor series and R for the radius of convergence.

In this case the coefficients of the Taylor series are

a_n = \frac{(-1)^{n+1}}{ n3^n}

and in consequence |a_n| = \frac{1}{3^nn}. Then,

\sqrt[n]{|a_n|} = \sqrt[n]{\frac{1}{3^nn}}

Applying the properties of roots

\sqrt[n]{|a_n|} = \frac{1}{3\sqrt[n]{n}}.

Hence,

R^{-1} = \lim_{n\rightarrow\infty} \frac{1}{3\sqrt[n]{n}} =\frac{1}{3}

Recall that

\lim_{n\rightarrow\infty} \sqrt[n]{n}=1.

So, as R^{-1}=\frac{1}{3} we get that R=3.

8 0
4 years ago
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