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balandron [24]
3 years ago
5

Help please! Ty!! ----

Mathematics
1 answer:
Tresset [83]3 years ago
3 0

Answer:

5 4/9

Step-by-step explanation:

9 x 5 + 4= 5 4/9

BRAINLIEST PLZAESE

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Explain how to use the vertex and the value of “A” to determine the range of an absolute value function. PLEASE HELP!!
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Answer:

First, a absolute value function is something like:

y = f(x) = IxI

remember how this work:

if x ≥ 0, IxI = x

if x ≤ 0, IxI = -x

Notice that I0I = 0.

And the range of this function is all the possible values of y.

For example for the parent function IxI, the range will be all the positive reals and the zero.

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Now, if the arms of the graph open up, then we know that A is the minimum of the function, and the range will be:

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if the arms of the graph open downwards, then A is the maximum of the function, and we have that the range is:

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quadrilateral WXYZ is reflected across the line y=x to create quadrilateral W’X’Y’Z'. What are the coordinates of quadrilateral
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Explanation

We are required to determine the coordinates of W’X’Y’Z' when WXYZ is reflected across the line y = x.

This is achieved thus:

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\begin{gathered} W(-7,3) \\ X(-5,6) \\ Y(-3,7) \\ Z(-2,3) \end{gathered}

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Therefore, we have:

\begin{gathered} (x,y)\to(y,x) \\ W(-7,3)\to W^{\prime}(3,-7) \\ X(-5,6)\to X^{\prime}(6,-5) \\ Y(-3,7)\to Y^{\prime}(7,-3) \\ Z(-2,3)\to Z^{\prime}(3,-2) \end{gathered}

Hence, the answers are:

\begin{gathered} \begin{equation*} W^{\prime}(3,-7) \end{equation*} \\ \begin{equation*} X^{\prime}(6,-5) \end{equation*} \\ \begin{equation*} Y^{\prime}(7,-3) \end{equation*} \\ \begin{equation*} Z^{\prime}(3,-2) \end{equation*} \end{gathered}

This is shown in the graph bwlow for further undertanding:

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