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kaheart [24]
3 years ago
14

1 hour = 3,600 seconds and 1 mile = 5,280 feet. Make a conjecture about how you could convert a speed of 15 miles per hour to fe

et per second. Then convert
Mathematics
1 answer:
MrRissso [65]3 years ago
6 0

Answer:

  multiply by feet per mile and divide by seconds per hour

Step-by-step explanation:

To get the desired units, multiply by a factor that is equal to 1, but has the desired units in the numerator and the units you're converting from in the denominator.

For units in the denominator that you want to change, use the inverse of the above multiplier.

We have miles/hour, which has miles in the numerator. We want feet/second, which has feet in the numerator, so we need to multiply by the ratio of feet per mile: 5280 ft/mi.

We also have hours in the denominator, where we want seconds. So, we divide by the factor 3600 s/h.

  \dfrac{15\,\text{mi}}{\text{h}}\cdot\dfrac{5280\,\text{ft}}{\text{mi}}\cdot\dfrac{\text{h}}{3600\,\text{s}}=22\,\text{ft/s}

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4 years ago
(ab^2 x -b^4a^3)^2<br><br> What is the answers
Umnica [9.8K]

Answer:

\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8

Step-by-step explanation:

Given the expression

\left(ab^2\:x\:-b^4a^3\right)^2

solving the expression

\left(ab^2\:x\:-b^4a^3\right)^2

\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a-b\right)^2=a^2-2ab+b^2

a=ab^2x,\:\:b=b^4a^3

so the expression becomes

=\left(ab^2x\right)^2-2ab^2xb^4a^3+\left(b^4a^3\right)^2

=a^2b^4x^2-2a^4b^6x+a^6b^8

Thus,

\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8

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3 years ago
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Answer:

x = -1 and y = 6

Step-by-step explanation:

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2 years ago
PLEASE! WILL GIVE METAL AND FAN.
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20000*0.45 = 9000 in the bond
20000*0.15 = 3000 in the CD
20000*0.20 = 4000 in stocks
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A=9000(1 + 4.35%)^3 = 10,226.33
A=3000(1 + 2.90%)^3 = 3,268.64
A=4000 (1 + 8%) x (1 - 4%) x (1 + 6%) = 4,396.03
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Total value = 22,436.04
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3 years ago
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Y=(2/5)x-4
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