Can someone explain to me how to answer questions like this? I always get confused!

Mathematics

1 answer:

seropon [69]3 years ago

5 0

Answer:

(b) 5k+1

Step-by-step explanation:

https://www.symbolab.com/solver/step-by-step/simplify%20%5Cfrac%7B30k%5E%7B2%7D%2B6k%7D%7B5k%2Bk%7D

You might be interested in

Firdavs [7]

Could you take a photo of the drawing?

5 0

3 years ago

I need help on this onee plizzzz

nika2105 [10]

(45+20)/(42+45+20+32)
65/139
46.762589928%

4 0

3 years ago

Read 2 more answers

Help me please how do I get the answer to 7.44 divided by 6 equals

dalvyx [7]

7.44 divided by 6 = 1.24
hopes this helps.

5 0

3 years ago

Read 2 more answers

Calculate the total area of the shaded region.

LUCKY_DIMON [66]

so hmmm seemingly the graphs meet at -2 and +2 and 0, let's check

$\stackrel{f(x)}{2x^3-x^2-5x}~~ = ~~\stackrel{g(x)}{-x^2+3x}\implies 2x^3-5x=3x\implies 2x^3-8x=0 \\\\\\ 2x(x^2-4)=0\implies x^2=4\implies x=\pm\sqrt{4}\implies x= \begin{cases} 0\\ \pm 2 \end{cases}$

so f(x) = g(x) at those points, so let's take the integral of the top - bottom functions for both intervals, namely f(x) - g(x) from -2 to 0 and g(x) - f(x) from 0 to +2.

$\stackrel{f(x)}{2x^3-x^2-5x}~~ - ~~[\stackrel{g(x)}{-x^2+3x}]\implies 2x^3-x^2-5x+x^2-3x \\\\\\ 2x^3-8x\implies 2(x^3-4x)\implies \displaystyle 2\int\limits_{-2}^{0} (x^3-4x)dx \implies 2\left[ \cfrac{x^4}{4}-2x^2 \right]_{-2}^{0}\implies \boxed{8} \\\\[-0.35em] ~\dotfill$

$\stackrel{g(x)}{-x^2+3x}~~ - ~~[\stackrel{f(x)}{2x^3-x^2-5x}]\implies -x^2+3x-2x^3+x^2+5x \\\\\\ -2x^3+8x\implies 2(-x^3+4x) \\\\\\ \displaystyle 2\int\limits_{0}^{2} (-x^3+4x)dx \implies 2\left[ -\cfrac{x^4}{4}+2x^2 \right]_{0}^{2}\implies \boxed{8} ~\hfill \boxed{\stackrel{\textit{total area}}{8~~ + ~~8~~ = ~~16}}$

7 0

2 years ago

The slope of the line below is 3. Use the coordinates of the labeled point (6, 8) to find a point-slope equation of the line.

Marina CMI [18]

point-slope equation

y - 8 = 3(x - 6)

hope it helps

5 0

3 years ago

Read 2 more answers