1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alekssandra [29.7K]
3 years ago
14

The fastest pizza box folder can assemble 2 pizza boxes in 5 seconds. At this rate, how long would it take to assemble 20 pizza

boxes?
Mathematics
1 answer:
gavmur [86]3 years ago
6 0

Answer:

50 seconds in order to assemble 20 pizza boxes

Step-by-step explanation:

there are two ways to solve this the first way is divide 20 by 2 which is 10 and then multiply 10 by 5 the reason to this is because we know that for every 2 it takes 5 seconds.

the second way takes longer but you write:

2, 2, 2, 2, 2, 2, 2, 2, 2, 2,

5, 5, 5, 5, 5, 5, 5, 5, 5, 5,

so here were basically writing the number 2 10 times because when u count that u can see that it equals 20 and then since for every 2 boxes it takes 5 seconds u put the 5 under each 2 so then you would count the 5s, like 5, 10 15, 20... and so on and u will see that its 50 which means 50 seconds.

You might be interested in
Tickets to a concert cost $2 for children, $3 for teenagers and $5 for adults. When 570 people attended the concert, the total t
-Dominant- [34]

Let

x--------> the number of children

y------> the number of teenagers

z------> the number of adults

we know that

2x+3y+5z=1,950 ------> equation A

x+y+z=570 -----> equation B

y=\frac{3}{4}x

x=\frac{4}{3}y -------> equation C

Substitute equation C in equation A and equation B

2[\frac{4}{3}y]+3y+5z=1,950

\frac{17}{3}y+5z=1,950 --------> equation D

[\frac{4}{3}y]+y+z=570

\frac{7}{3}y+z=570 --------> equation E

Multiply equation E by -5

-\frac{35}{3}y-5z=-2,850 --------> equation F

Adds equation D and equation F

\frac{17}{3}y+5z=1,950\\\\-\frac{35}{3}y-5z=-2,850\\\\---------\\\\-\frac{18}{3}y=-900\\\\y=3*900/18\\\\y=150\ teenagers

therefore

<u>the answer is the option</u>

150\ teenagers


4 0
3 years ago
Read 2 more answers
What is the value of 2 in 0.259
expeople1 [14]
The two is in the tenths place. 
4 0
3 years ago
Read 2 more answers
The base of a circular fence with radius 10 m is given by x = 10 cost, y = 10 sin t. the height of the fence at position (x, y)
antiseptic1488 [7]

The parametric equations for x and y describe a circle of radius 10 m, so the length of the base of the fence is the length of the circumference of a circle of radius 10 m. The formula for that circumference (C) is ...

... C = 2πr

... C = 2π·(10 m) = 20π m

The height as a function of angle (t) is found by substituting for x and y.

... h(t) = h(x(t), y(t)) = 4 + 0.01·((10cos(t))²-)10sin(t))²) = 4+cos(2t)

The average value of this over the range 0 ≤ t ≤ 2π is 4, since the cosine function has two full cycles in that range, and its average value over a cycle is zero.

Thus, the area of one side of the fence is that of a rectangle 20π m long and 4 m wide. That will be

... (20π m)·(4 m) = 80π m²

The amount of paint required to cover both sides of the fence is

... 2×(80π m²)×(1 L)/(10 m²) = 16π L ≈ 50.3 L

_____

You can work out the integral for area as a function of t. When you do, you will find it gives this same result.

5 0
3 years ago
Please help! i need to pass this class!!
torisob [31]

Angle B = 54°

Step-by-step explanation:

complimentary means they add up to 90

54 + 36 (angle A) = 90

also x= 51

3 0
3 years ago
Read 2 more answers
) f) 1 + cot²a = cosec²a​
notsponge [240]

Answer:

It is an identity, proved below.

Step-by-step explanation:

I assume you want to prove the identity. There are several ways to prove the identity but here I will prove using one of method.

First, we have to know what cot and cosec are. They both are the reciprocal of sin (cosec) and tan (cot).

\displaystyle \large{\cot x=\frac{1}{\tan x}}\\\displaystyle \large{\csc x=\frac{1}{\sin x}}

csc is mostly written which is cosec, first we have to write in 1/tan and 1/sin form.

\displaystyle \large{1+(\frac{1}{\tan x})^2=(\frac{1}{\sin x})^2}\\\displaystyle \large{1+\frac{1}{\tan^2x}=\frac{1}{\sin^2x}}

Another identity is:

\displaystyle \large{\tan x=\frac{\sin x}{\cos x}}

Therefore:

\displaystyle \large{1+\frac{1}{(\frac{\sin x}{\cos x})^2}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{1}{\frac{\sin^2x}{\cos^2x}}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}

Now this is easier to prove because of same denominator, next step is to multiply 1 by sin^2x with denominator and numerator.

\displaystyle \large{\frac{\sin^2x}{\sin^2x}+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}\\\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}

Another identity:

\displaystyle \large{\sin^2x+\cos^2x=1}

Therefore:

\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}\longrightarrow \boxed{ \frac{1}{\sin^2x}={\frac{1}{\sin^2x}}}

Hence proved, this is proof by using identity helping to find the specific identity.

6 0
3 years ago
Other questions:
  • In triangle △ABC, ∠ABC=90°, BH is an altitude. Find the missing lengths. AC=5 and BH=2, find AH and CH.
    7·1 answer
  • An object’s speed decreases by 6% for each minute that it is slowing down. What is the percent that it’s speed will decrease ove
    6·1 answer
  • Gcf and lcm of 6 and 9
    9·1 answer
  • Parker drew a triangle with no cogruent sides and a 95° angle. Classify the triangle by the lengths of its sides and measures of
    9·1 answer
  • Simplify. Round your answer to three decimal places.<br><br> 1<br> 2<br> ·<br> 2<br> 3<br> + 0.345
    8·1 answer
  • PLEASE HELP! WILL MARK BRAINLIEST ANSWER!
    9·2 answers
  • Help me with my math please??
    7·2 answers
  • How is subtracting integers related to the addition of integers?
    11·1 answer
  • Identify the equivalent expression to the square root of x plus 3
    5·1 answer
  • For the function y = 3x, if the input (x) is -2, what is the output (y) ?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!