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zavuch27 [327]
3 years ago
14

Which of the following is a root of the polynomial shown below? f(x)=x^3-x^2-9x+9

Mathematics
2 answers:
maxonik [38]3 years ago
8 0

Answer:

-3 is the best answer i hope it helps


Step-by-step explanation:


ira [324]3 years ago
4 0

We have been given a polynomial function f(x)=x^3-x^2-9x+9. We are asked to choose the root of the function from given choices.

Let us set our polynomial equal to 0.

x^3-x^2-9x+9=0

Now we will factor our polynomial by grouping method.

(x^3-x^2)+(-9x+9)=0

Let us factor out greatest common factor from each group.

x^2(x-1)-9(x-1)=0

(x-1)(x^2-9)=0

We can further factor (x^2-9) using difference of squares.

(x-1)(x^2-3^2)=0

(x-1)(x+3)(x-3)=0

Using zero product property, we will get:

(x-1)=0\text{ (or) }(x+3)=0\text{ (or) }(x-3)=0

x=1\text{ (or) }x=-3\text{ (or) }x=3

Upon looking at our given choices, we can see that -3 is the correct choice, therefore, -3 is root of the given polynomial.

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Step-by-step explanation:

8 0
3 years ago
A rectangular garden has a length of (2y - 4) feet and a width of 4y^2 feet. How do you find the perimeter of the garden
Ber [7]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{8 {y}^{2}  + 4y - 8}}}}}

Step-by-step explanation:

Given,

Length of a rectangular garden ( l ) = 2y - 4

Width of a rectangular garden ( w ) = 4y²

Perimeter of the garden = ?

<u>Finding</u><u> </u><u>the</u><u> </u><u>perimeter</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangular</u><u> </u><u>garden</u><u> </u><u>having </u><u>length </u><u>of</u><u> </u><u>2</u><u>y</u><u>-</u><u>4</u><u> </u><u>and</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>4</u><u>y</u><u>²</u>

\bold{ \boxed{ \sf{perimeter \: of \: a \: rectangle = 2(l + w)}}}

\longrightarrow{ \sf2(2y - 4 + 4 {y}^{2}})

Distribute 2 through the parentheses

\longrightarrow{ \sf{4y - 8 + 8 {y}^{2} }}

Arrange it in standard form

\longrightarrow{ \sf{8 {y}^{2}  + 4y - 8}}

Hope I helped!

Best regards! :D

3 0
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We would need to know the measurements of the circle to answer this  
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