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Butoxors [25]
3 years ago
15

To the nearest square inch, what is the area of the shaded sector in the circle shown below

Mathematics
2 answers:
irina1246 [14]3 years ago
8 0
Don't see the circle
egoroff_w [7]3 years ago
6 0
We would need to know the measurements of the circle to answer this  
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The height (in ft) of an object over time(in seconds) is modeled by the function h(t)=-6t^2+23t+7. How high is the object after
riadik2000 [5.3K]

About 4.1 seconds. How long was the ball in the air? We are told that t represents time in seconds since the ball was thrown, so it started to be 'in the air' at t = 0 To answer the question, then, we need to know the time when it stopped being in the air. We are told that the ball hit the ground. So that's what happened when it stopped being airborne. We need to relate that event to the mathematics we're working with. What can we say about h , the height of the ball when the ball hits the ground? Answer: The height will be 0 when the ball stops being in the air. Now translate this back to the mathematics: The ball is in the air from t = 0 until the time t when h = 0 . Find the time t that makes h = 0 . That means: solve: − 5 t 2 + 20 t + 2 = 0 We can solve this by solving: 5 t 2 − 20 t − 2 = 0 (Either multiply both sides of the equation by − 1 , or add 5 x 2 − 20 x and − 2 to both sides and then re-write it the other way around) That's a quadratic equation, so try to factor first. But don't spend too much time trying to factor, because not every quadratic is easily factorable and that's OK, because we still have the quadratic formula if we need it. We do need it. t = − ( − 20 ) ± √ ( − 20 ) 2 − 4 ( 5 ) ( − 2 ) 2 ( 5 ) = 20 ± √ 440 10 = 20 ± √ 4 ( 110 ) 10 = 20 ± 2 √ 110 10 = 2 ( 10 ± √ 110 ) 2 ( 5 ) = 10 ± √ 110 5 We can see that 10 < √ 110 < 11 . In fact ( 10 + 1 2 ) 2 = 10 2 + 10 + 1 4 = 110.25 Using 10.25 as an approximation for √ 110 , we get : for the solution t = 10 − √ 110 5 we'll get a negative t . That doesn't make sense. The other solution gives t ≈ 10 + 10.25 5 = 20.5 5 = 4.1 seconds. So the ball was in the air from t = 0 until about t = 4.1 . The elapsed time is the difference, 4.1 seconds.

5 0
2 years ago
Zoe counts 5 times as many black kittens as white kittens for sale at the pet store. she counts a total of 25 kittens how many m
malfutka [58]

Let us say that:

a = black kittens

b = white kittens

 

We know that:

a = 5 b

a + b = 25

 

Therefore:

5 b + b = 25

6 b = 25

b = 4.17

But we cannot have a fraction value for the number of kittens, so round off:

b = 4

 

So a is:

a = 25 – 4 = 21

 

<span>Hence Zoe counts additional 1 black kitten.</span>

3 0
2 years ago
a store wants to print flyers to advertise it's grand opening. A printer will charge $50 and $0.05 per flyer. if the store has a
Vinvika [58]

The equation would be  .05x+50=100 Then you would solve for x

7 0
3 years ago
36-9 divided [(0.24*5)+ (0.66*5)]
Ray Of Light [21]
[(0.24*5)+ (0.66*5)] == 4.50
0.24x5 = 1.20
0.66x5 = 3.30
+ ____
4.50

27.00÷4.5 = 0.166666667
4 0
3 years ago
If f(x)=2x-5, which expression represents f(x+1)? A) 2x-3, B) 2x-4, C)2x-5, D)2x+7
Dovator [93]
F(x)=x^2+2x+1 & g(x)=3(x+1)^2
now, f(x)+g(x)
=x^2+2x+1+3(x+1)^2
=x^2+2x+1+3(x^2+2x+1)
=x^2+2x+1+3x^2+6x+3
=4x^2+8x+4<===answer(c)
next:
f(x)=x^2-1 & g(x)=x+3
now, f(g(x))=(x+3)^ -1
=x^2+6x+9-1
=x^2+6x+8<====answer(b)
i solve two of ur problems.
now try the 3rd one that is similar to no. 1
and try the last two urself.
5 0
3 years ago
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