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AURORKA [14]
4 years ago
10

A rectangular garden has a length of (2y - 4) feet and a width of 4y^2 feet. How do you find the perimeter of the garden

Mathematics
1 answer:
Ber [7]4 years ago
3 0

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{8 {y}^{2}  + 4y - 8}}}}}

Step-by-step explanation:

Given,

Length of a rectangular garden ( l ) = 2y - 4

Width of a rectangular garden ( w ) = 4y²

Perimeter of the garden = ?

<u>Finding</u><u> </u><u>the</u><u> </u><u>perimeter</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangular</u><u> </u><u>garden</u><u> </u><u>having </u><u>length </u><u>of</u><u> </u><u>2</u><u>y</u><u>-</u><u>4</u><u> </u><u>and</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>4</u><u>y</u><u>²</u>

\bold{ \boxed{ \sf{perimeter \: of \: a \: rectangle = 2(l + w)}}}

\longrightarrow{ \sf2(2y - 4 + 4 {y}^{2}})

Distribute 2 through the parentheses

\longrightarrow{ \sf{4y - 8 + 8 {y}^{2} }}

Arrange it in standard form

\longrightarrow{ \sf{8 {y}^{2}  + 4y - 8}}

Hope I helped!

Best regards! :D

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