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4 years ago

A rectangular garden has a length of (2y - 4) feet and a width of 4y^2 feet. How do you find the perimeter of the garden

Mathematics

1 answer:

Ber [7]4 years ago

3 0

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{8 {y}^{2} + 4y - 8}}}}}$

Step-by-step explanation:

Given,

Length of a rectangular garden ( l ) = 2y - 4

Width of a rectangular garden ( w ) = 4y²

Perimeter of the garden = ?

Finding the perimeter of a rectangular garden having length of 2y-4 and width of 4y²

$\bold{ \boxed{ \sf{perimeter \: of \: a \: rectangle = 2(l + w)}}}$

$\longrightarrow{ \sf2(2y - 4 + 4 {y}^{2}})$

Distribute 2 through the parentheses

$\longrightarrow{ \sf{4y - 8 + 8 {y}^{2} }}$

Arrange it in standard form

$\longrightarrow{ \sf{8 {y}^{2} + 4y - 8}}$

Hope I helped!

Best regards! :D

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