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Sonbull [250]
4 years ago
8

What is the inverse of log(6)

Mathematics
1 answer:
crimeas [40]4 years ago
5 0

inverse of log(6) is 1.28

<u>Step-by-step explanation:</u>

We have  , a expression log(6) . Let y = log(6) . We need to find inverse of y .

Let inverse of y be y^{-1 . So we know that multiplication of y and i'ts inverse will be 1 i.e.

⇒ y(y^{-1}) = 1

⇒ \frac{yy^{-1}}{y} = \frac{1}{y}

⇒ y^{-1} = \frac{1}{y}

but y = log6

⇒ y^{-1} = \frac{1}{Log(6)}                     { log6 = 0.778  }

⇒ y^{-1} = \frac{1}{0.778}

⇒ y^{-1} =1.28

Therefore, inverse of log(6) is 1.28

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Given:

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Distance between two point is:

\begin{gathered} (x_1,y_1)and(x_2,y_2) \\ D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \end{gathered}

so distance between A(-5,4) and B(3,4) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(4-4)^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

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\begin{gathered} D=\sqrt[]{(3-3)^2+(-5-4)^2} \\ =\sqrt[]{0^2+(-9)^2} \\ =9 \end{gathered}

So BC is 9 unit apart.

For fourth bush point is (-5,-5) it left of point C(3,-5) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(-5-(-5))^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

so fourth bush is 8 unit left of C.

For fourth bush(-5,-5) below to point A(-5,4)

\begin{gathered} D=\sqrt[]{(-5-(-5))^2+(4-(-5))^2} \\ =\sqrt[]{0^2+9^2} \\ =9 \end{gathered}

so fourth bush 9 units below of A.

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