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ki77a [65]
3 years ago
11

If 52/x is a positive integer, how many integer values are possible for x?

Mathematics
1 answer:
vekshin13 years ago
4 0
Since there are 6 factors of 52 (1, 2, 4, 13, 26, 52), the answer is 6
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The equation x2+px−35=0 has one root that is equal to 7. Find the other root and the value of the coefficient p.
Usimov [2.4K]
For this case we have the following polynomial:
 x2 + px-35 = 0
 We can factor the polynomial.
 Rewriting we have:
 (x-7) * (x + a) = 0
 The value of a is given by:
 -7 * a = -35
 a = 35/7
 a = 5
 Substituting we have:
 (x-7) * (x + 5) = 0
 Therefore, the value of p is:
 p = -7 + 5
 p = -2
 Answer:
 
the other root is:
 
x = -5
 
The value of the coefficient is:
 
p = -2
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3 years ago
Please help!<br> f(x)=x^2 what is g(x)
Anon25 [30]

A.

Observe that point (3,3) can only be obtained via function A: \frac{1}{3}3^2=3.

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\frac{1}{9}3^2\neq3

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(\frac{1}{3}\cdot3)^2\neq3

Hope this helps :)

5 0
3 years ago
Christian and Megan want to purchase a new car. The car has a base price of $16,700, options totaling $1,095, and a destination
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(a) Triangle ABC is similar to triangle AED because angle BAC is congurent to angle EAD and angle ADE is also congurent to angle ACB.

(b) The distance from C and to the line through AB is 9.5.

(c) The length AE IS 3.16

(d) Angle BAC is 71.565⁰.

(e) The shortest distance from C to E is 8.99.

(f) The area of ​​the whole figure is 37.53 sq unit.

<h3>Similar triangles</h3>

Triangle ABC is similar to triangle AED because angle BAC is congurent to angle EAD and angle ADE is also congurent to angle ACB.

<h3>Distance from C and to the line through AB</h3>

Let the distance from C and to the line through AB = h

BC = 10

Line through C divides the angle into two, = ¹/₂ x 36.87⁰ = 18.435⁰

Angle B = 90 - 18.435⁰ = 71.565⁰

Sin71.565⁰ = h/10

h = 10 x Sin71.565⁰

h = 9.5

<h3>Length of AE</h3>

\frac{AB}{BC} = \frac{AE}{DE} \\\\\frac{6.32}{10} = \frac{AE}{5} \\\\AE = 3.16

<h3>Angle BAC</h3>

BAC = 180 - (36.87  + 71.565)

BAC = 71.565⁰

also, since AC = BC, angle B = angle A =  71.565⁰

<h3>Shortes distance from C to E</h3>

The shortest distance from C to E is a vertical line that connects C and E.

Let the vertical line = h

|BA| + |AE| = 6.32 + 3.16 = 9.48

sinB = h/9.48

h = 9.48 x sinB

h = 9.48 x sin71.565

h = 8.99

<h3>Height of triangle ADB</h3>

\frac{height \ of \ ADE}{base \ ADE} = \frac{height \ of \ ACB}{base \ ACB}\\\\\frac{h}{3.16} = \frac{9.5}{6.32} \\\\h = 4.75

<h3>Area of the whole figure</h3>

Total area = Area of ADE + Area of ACB

A = ¹/₂x base x height + ¹/₂ x base x height

A = ¹/₂ x 3.16 x 4.75  + ¹/₂ x 6.32 x 9.5

A = 37.53 sq unit

Learn more about similar triangles here: brainly.com/question/11899908

#SPJ1

7 0
2 years ago
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