Answer:
[B] 0, 19.5, 160.5, 180, 360
Step-by-step explanation:
3 sin²θ = sin θ
3 sin²θ − sin θ = 0
sin θ (3 sin θ − 1) = 0
sin θ = 0 or sin θ = ⅓
If sin θ = 0, θ = 0°, 180°, 360°.
If sin θ = ⅓, θ = 19.5°, 160.5°.
876,543
7 is <span>tens of thousands.</span>
Answer:
<h2>
Function is
y = x.</h2><h2>
Domain: 
.</h2><h2>
Range: 
.</h2>
Step-by-step explanation:
In the given image, the line passes through (-1, -1) and (1, 1).
Let the equation of the line is 
, where m is the tangent of the line and c is a constant.
Putting the co-ordinates of the points in the equation, we get 
and 
From the two equations we get, c = 0 and m = 1.
Hence, the function is y = x.
Domain is .
Range is
BY USING MIDDLE TERM SPLITTING,
3y^2-(3y-2y)-2
(3y^2-3y)+(2y-2)
3y(y-1)+2(y-1)
(3y+2)(y-1)
HOPE THIS WILL HELP U
Answer:
<h3>
f(x) = - 3(x + 8)² + 2</h3>
Step-by-step explanation:
f(x) = a(x - h)² + k - the vertex form of the quadratic function with vertex (h, k)
the<u> axis of symmetry</u> at<u> x = -8</u> means h = -8
the <u>maximum height of 2</u> means k = 2
So:
f(x) = a(x - (-8))² + 2
f(x) = a(x + 8)² + 2 - the vertex form of the quadratic function with vertex (-8, 2)
The parabola passing through the point (-7, -1) means that if x = -7 then f(x) = -1
so:
-1 = a(-7 + 8)² + 2
-1 -2 = a(1)² + 2 -2
-3 = a
Threfore:
The vertex form of the parabola which has an axis of symmetry at x = -8, a maximum height of 2, and passes through the point (-7, -1) is:
<u>f(x) = -3(x + 8)² + 2</u>
