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3 years ago

This will take the smartest brainly player Give explanation

Mathematics

1 answer:

ratelena [41]3 years ago

6 0

Answer:

n^6 is the answer

$n^{6} * n^{\frac{1}{4} } = n^{\frac{25}{4} }$

$\frac{1}{\sqrt[4]{n} } * n^{\frac{25}{4} } = \frac{n^{\frac{25}{4} } }{n^{\frac{1}{4} } } = n^{\frac{25}{4} } - n^{\frac{1}{4} } = n^{6}$

Step-by-step explanation:

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Please help with this

Assoli18 [71]

Answer:

the answer is 34567

Step-by-step explanation:

im not lying just to get points

8 0

3 years ago

Mia is babysitting and has $40 to give to the 5 kiddos for snacks at the movie theater. How much money will each of the children

Tcecarenko [31]

Answer:

Each child would get $8.00.

Step-by-step explanation:

An equation to represent this would be:

40/5

When you divide 40 by 5, you get 8 which results in the children each getting $8.00

6 0

3 years ago

Read 2 more answers

Which expression is equal to p + (q + r)?

Svetach [21]

The answer should be a) (p+q)*r

7 0

3 years ago

A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739

OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

For a constant acceleration: $v_{f}=v_{0}+at$ , where $v_{f}$ is the final velocity in a direction after the acceleration is applied, $v_{0}$ is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
<em>Then for the x direction</em> it is known that the initial velocity is $v_{0x} =$ 5320 m/s, the acceleration (the applied by the engine) in x direction is $a_{x}$ 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then: $v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}$
In the same fashion, <em>for the y direction</em>, the initial velocity is $v_{0y} =$ 0 m/s, the acceleration in y direction is $a_{y}$ 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: $v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}$

8 0

3 years ago

12 is to 60 as 5 is to ?

Elina [12.6K]

12:60 equals to 5:25

4 0

3 years ago